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Leviafan [203]
2 years ago
6

Which property of an ice cube will stay the same after the ice cube is melted?

Chemistry
2 answers:
Mademuasel [1]2 years ago
4 0

Answer:

C. Mass

Explanation:

ryzh [129]2 years ago
3 0

Mass
Thanks me later
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Write the word and balanced chemical equations for the reaction between:
nadezda [96]

Answer:

3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

Explanation:

An acid reacts with a base producing water and a salt. Having this in mind the reaction of nitric acid (HNO₃) and Iron (III) hydroxide (Fe(OH)₃) is:

HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

<em>The H⁺ of the acid reacts with the OH⁻ to produce H₂O. The other ions (Fe³⁺ and NO₃⁻) produce the salt</em>

<em />

There are 3 nitrates in products. To balance the nitrates:

<h3>3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃</h3>

<em>And this is the balanced reaction</em>

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3 0
3 years ago
Olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. How will the new soles h
HACTEHA [7]
Maybe her old shoes had soft worn out bottoms and she slips in them. So her new shoes had more grip than her old ones so they kept her from falling.
6 0
2 years ago
Read 2 more answers
What do you mean by antibodies​
eduard
Ans: a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
8 0
2 years ago
A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
BRAINLIESTTT ASAP!!! PLEASE HELP ME :))
garri49 [273]

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Given: [1 gram = 0.04 ounce, 1 liter = 1,000 milliliter]

1.25 x 0.04 = 0.05 oz

Therefore, 0.05 per 1,000 milliliter

0.05 ÷ 1,000 = 0.00005 oz

Therefore, the density of the gas is 0.00005 oz/mL

Hope this helps! :)

6 0
2 years ago
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