Answer:
8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.
Explanation:
Moles of ethanol of ethanol = 0.200 mol
Heat required to heat 0.200 moles of ethanol = Q = 1.05 kJ
Enthalpy of vaporization of ethanol =
Heat required to vaporize 0.200 moles of ethanol = Q'
Total heat required to fore heating and the vaporizing :
= Q + Q' = 1.05 kJ + 7.72 kJ = 8.77 kJ
8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.
Answer:
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- <u><em>3.42 moles</em></u>
Explanation:
By the law of conservation of energy, assuming no losses of heat to the surroundings, <em>the amount of heat consumed by the dissolution of the ammonium nitrate is equal to the amount of heat released from the water.</em> This is, the ammonium nitrate absorbs all the heat it needs to break the ions apart and get dissolved from the water in which it is being dissolved.
Thus:
↑ ↑ ↑
heat released number of moles molar heat of solution
from water of NH₄NO₃ for NH₄NO₃
Solve for n and compute:
- n = 88.0kJ / (25.7kJ/mol) = 3.42 moles ← answer