Copper<span>(II) </span>oxide<span> or cupric </span>oxide<span> is the inorganic </span>compound<span> with the formula CuO. A black solid, it is one of the two stable </span>oxides<span> of </span>copper, the other being Cu2<span>O or cuprous </span>oxide<span>. As a mineral, it is known as tenorite and paramelaconite.</span>
To calculate the mean, you add up all of the data values, and then divide that sum by the *number* of values.
For instance, if you wanted to find the mean score at a home run derby, and you’re given the following numbers for home runs scored by each player:
5, 4, 6, 5, 3, 1
You could calculate the mean by adding all of the score up
5 + 4 + 6 + 5 + 3 + 1 = 24
And dividing by the number of hitters (in this case, 6)
24 / 6 = 4
So the *mean score* of the home run derby would be 4.
Answer:
A
Explanation:
CHEMICALS WEATHER IN CHEMICAL WEATHERING
Answer:
(a) 7.11 x 10⁻³⁷ m
(b) 1.11 x 10⁻³⁵ m
Explanation:
(a) The de Broglie wavelength is given by the expression:
λ = h/p = h/mv
where h is plancks constant, p is momentum which is equal to mass times velocity.
We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.
v = 19.8 mi/h x ( 1609.34 m/s ) x ( 1 h / 3600 s ) = 8.85 m/s
m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg
λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m
(b) For this part we have to use the uncertainty principle associated with wave-matter:
ΔpΔx > = h/4π
mΔvΔx > = h/4π
Δx = h/ (4π m Δv )
Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.
Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )
= 0.045 m/s
Δx = h/ (4π m Δv ) = 6.626 x 10⁻³⁴ J·s / (4π x 105.33 kg x 0.045 m/s )
= 1.11 x 10⁻³⁵ m
This calculation shows us why we should not be talking of wavelengths associatiated with everyday macroscopic objects for we are obtaining an uncertainty of 1.11 x 10⁻³⁵ m for the position of the fullback.
