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miskamm [114]
4 years ago
7

A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is

700 kg, and the total resistance (air drag plus friction with the runway) on each may be assumed constant and equal to 1600 N. The tension in the towrope between the transport plane and the first glider is not to exceed 12000 N. A)If a speed of 40 { m/s} is required for takeoff, what minimum length of runway is needed? B)What is the tension in the towrope between the two gliders while they are accelerating for the takeoff?
Physics
1 answer:
Ksenya-84 [330]4 years ago
8 0

Answer:

The total resistance is 5000 N. So the net force left for acceleration is 7 000 N (12 000 - 5 000).

7000 N applied to 2x700 kg gives a maximum acceleration of

a = F/m = 7000/1400kg = 5 m/s^2

At 5m/s^2, it will take 8 s to reach 40 m/s. In 8 second the distance covered will be

d = 1/2 at^2 = 1/2 x 5 x 8^2 = 160 m

Because each glider has the same drag and inertia, the tension in the rope between the gliders will be exactly half of the tension between plane and the two gliders:

12 000/2 = 6 000N.

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Answer: TRUE

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A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0
4 years ago
In a transformer, energy is carried from the primary coil to the secondary coil by:________
likoan [24]

In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.

To find the answer, we have to know more about the transformer.

<h3>How transformer works?</h3>
  • An item utilized in the transfer of electric energy is a transformer.
  • AC current is used for transmission.
  • It is frequently used to modify the supply voltage between circuits without altering the AC frequency.
  • The fundamentals of mutual and electromagnetic induction govern how the transformer operates.
  • Magnetic field through the primary coil changes when primary coil current varies. the iron core of the secondary coil likewise has a magnetic field.
  • EMF is therefore generated in the secondary coil.

Thus, we can conclude that, in a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.

Learn more about the transformer here:

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5 0
2 years ago
Light does not move infinitely fast but has a finite speed. We normally use ""c"" to indicate the speed of light in science. Wri
Ede4ka [16]

Answer:

6.71 × 10^8 mi/hr

Explanation:

Light is usually defined as an electromagnetic wave that is comprised of a definite wavelength. It is of both types, visible and invisible. The light emitted from a source usually travels at a speed of about 3 × 10^8 meter/sec. This speed of light is commonly represented by the letter 'C'.

To write it in the metric system, it has to be converted into miles/hour.

We know that,

1 minute = 60 seconds

60 minutes = 1 hour

1 kilometer = 1000 meter

1 miles = 1.6 kilometer

Now,

= \frac{3 \times\ 10^8 meter \times\ 60 sec \times\ 60 min}{1 sec \times\ 1 min \times\ 1 hr}

= 1.08 × 10^12 m/ hr (meter/hour)

= \frac{1.08 \times\ 10^{12} meter \times\ 1 km \times\ 1 miles}{1 hr \times\ 1000 meter \times\ 1.6 km}

= 6.71 × 10^8 mi/hr (miles/hour)

Thus, the value for speed of light (C) in metric unit is 6.71 × 10^8 mi/hr.

5 0
4 years ago
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