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Mkey [24]
3 years ago
11

The body’s pH is tightly regulated because specific enzymes function best within a narrow pH range. What is the approximate pH o

f a 1.2 × 10–5 M aqueous solution of NaOH?
Chemistry
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

The answer to your question is pH = 9.08

Explanation:

Data

pH = ?

Concentration = 1.2 x 10⁻⁵ M

Process

1.- Calculate the pOH of the solution

Formula

   pOH = -log[OH⁻]

   pOH = -log[1.2 x 10⁻⁵]

   pOH = 4.92

2.- Calculate the pH

Formula

    pH = 14 - pOH

Substitution

    pH = 14 - 4.92

Result

    pH = 9.08    

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3 0
2 years ago
How many moles of NaCl are in 2,719 mL of a 6.32 M solution?
Mademuasel [1]

Answer:

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Explanation:

Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

6.32 M=\frac{n}{2.719 L}

n=6.32M\times 2.719 L=17.18 mol

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

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4 years ago
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7 0
3 years ago
Read 2 more answers
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu
vlabodo [156]

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

                          M_{1}V_{1}=M_{2}V_{2}     EQUATION (1)


Here, we have:

 M_{1} = 3M

  V_{1}  = y mL

M_{2}= 1.80 M

V_{2} = 50.0mL

putting the known values in equation (1) which will give us value of V_{1}

                                         3.00× y =1.80 ×50.0

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3 0
4 years ago
Read 2 more answers
Choose the best answer.<br> What is the sum?<br> 2/3+7/15<br> O 14/15<br> O1/2<br> O1 2/15<br> O3/5
Fudgin [204]

Answer:

1 2/15

Explanation:

2/3 + 7/15 = 17/15 =1 2/15

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2 years ago
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