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3 years ago

What are the cahnges that a force can bring out on a body ? Give examples

2 answers:

5 0

Hi Pupil Here is your answer ::

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1 The shape of the Body

Example : The shape of the ball lying on a floor can be changed by pressing it.

2 Direction of the Body

Example : The direction of motion of moving ball can be changed by hitting it with a bat.

3 The speed of the Body

Example : A ball at rest can be set in motion if force is applied only

4. Size of the Body

Example : The length of a spring tied and on one end can be increased by pulling it.

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Hope this helps .......

Serggg [28]3 years ago

5 0

See above and enjoy

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1.What is an object that appears fuzzy through a material that is?

Anna007 [38]

Answer:

not sure 5

but thaks for the points

7 0

3 years ago

Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fi

nydimaria [60]

Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.

Hope it helped! :>

4 0

3 years ago

At a certain time a particle had a speed of 48 m/s in the positive x direction, and 4.5 s later its speed was 92 m/s in the oppo

larisa86 [58]

Answer:

$-31.1 m/s^2$

Explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is calculated as:

$a=\frac{v-u}{t}$

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it is important to also take into account the direction of the velocity.

For the particle in this problem, we have:

u = +48 m/s is the initial velocity (positive direction)

v = -92 m/s is the final velocity (negative direction)

t = 4.5 s is the time interval

Therefore, the average acceleration is

$a=\frac{v-u}{t}=\frac{-92-(+48)}{4.5}=-31.1 m/s^2$

4 0

3 years ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

spayn [35]

Answer:

$v_0 = 3.53~{\rm m/s}$

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

$x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}$