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3 years ago

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As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o

n the floor by the heel if it has an area of 1.50 cm2 and the woman’s mass is 55.0 kg. Express the pressure in Pa. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were to

1 answer:

astraxan [27]3 years ago

6 0

Answer:

3.6 x 10⁶ Pa

Explanation:

A = Area of the heel = 1.50 cm² = 1.50 x 10⁻⁴ m²

m = mass of the woman = 55.0 kg

g = acceleration due to gravity = 9.8 m/s²

Force of gravity on the heel is given as

F = mg

Inserting the values

F = (55) (9.8)

F = 539 N

Pressure exerted on the floor is given as

$P = \frac{F}{A}$

$P = \frac{539}{1.5\times 10^{-4}}$

P = 3.6 x 10⁶ Pa

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Suppose two equal mass cars traveling with equal speeds in opposite directions inelasticcollide head on and stick together. What

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In an inelastic collision, we have;

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Therefore, <u>all the kinetic energy is dissipated</u>

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3 years ago

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3 years ago

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Rzqust [24]

<u>Answer: </u>

Maximum height reached by the ball thrown up at 30m/s is 3.06 seconds and the height reached is 45.9 meters

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Solution:

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Using the formula

$v^{2}-u^{2}=2 a s$

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Substituting values

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$s=45.9 \text { meters }$

Result:

Thus the maximum height reached is 45.9 meters in 3.06 seconds

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3 years ago

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