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solniwko [45]
2 years ago
12

When does sound become damaging to the human ear?

Physics
1 answer:
Vlad1618 [11]2 years ago
5 0
When someone yells in it
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a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed
Juliette [100K]
  • Mass of the car (m) = 2000 Kg
  • Initial velocity (u) = 15 m/s
  • Force (F) = 10000 N
  • Time (t) = 3 s
  • Let the acceleration be a.
  • By using the formula, F = ma, we get,
  • 10000 N = 2000 Kg × a
  • or, a = 10000 N ÷ 2000 Kg
  • or, a = 5 m/s^2
  • Let the final velocity be v.
  • By using the formula, v = u + at, we get,
  • v = 15 m/s + 5 m/s^2 × 3 s
  • or, v = 15 m/s + 15 m/s
  • or, v = 30 m/s

<u>Answer</u><u>:</u>

<em><u>The </u></em><em><u>new </u></em><em><u>sp</u></em><em><u>e</u></em><em><u>ed </u></em><em><u>of </u></em><em><u>the </u></em><em><u>car </u></em><em><u>is </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
A ball is dropped from the top of a tall building. As the ball falls, the upward force of air rsistance becomes equal to the dow
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Fall at a constant speed

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3 years ago
Anino acids are important to the body because they build
tino4ka555 [31]

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Amino acids and proteins are the building blocks of life. When proteins are digested or broken down, amino acids are left. The human body uses amino acids to make proteins to help the body: Break down food.

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3 years ago
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As the ambulance got closer, Marge noticed that the pitch of the siren got higher. This happened because
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A) the sound waves were pushed closer together

6 0
3 years ago
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A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d
prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance  

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

V_{t}= V_{o}e^{\frac{-t}{R*C} }

Voltage in this case is the energy dissipated so

E_{t}= E_{o}e^{\frac{-t}{R*C} }

\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }

\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }

Using the equation to find capacitance

ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }

C= 5.32x10^{-6} F

C= 5.32 uF because u is the symbol for micro that is equal to 10^{-6}

8 0
3 years ago
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