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padilas [110]
3 years ago
11

Use calc to determine whether it is possible to remove 99.99% Cu2 by converting it to Cu(s) in a solution mixture containing 0.1

2 Cu2 and 0.12 MSn2 suppose it is at room temperature.
Chemistry
1 answer:
inessss [21]3 years ago
7 0

Answer:

it is possible to remove 99.99% Cu2 by converting it to Cu(s)

Explanation:

So, from the question/problem above we are given the following ionic or REDOX equations of reactions;

Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V

Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V

In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:

Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.

Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.

Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.

Thus, ΔG° = - 92640.

This is less than zero[0]. Therefore,  it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.  

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Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i
alina1380 [7]

Answer:

  • <em>Number of protons, Z = 14</em>
  • <em>Number of neutrons, N = 14</em>

Explanation:

<u>1) About isotopes:</u>

<em>Isotopes</em> are different kind of atoms of the same element. Hence, they have the atomic number (Z), which is the number of <em>protons</em>, the same number of electrons (talking about to neutral atoms, not ions), and different <em>number of neutrons N).</em>

This is, it is the number of neutrons what distinguish different isotopes of an element.

<u>2) About the notation used to distinguish different isotopes:</u>

A superscript and a subscript, both to the left of the chemical symbol of the element, are used to <em>distinguish different isotopes</em>:

       A ←------------- This superscript tells the mass number of the isotope

           X ←--------- This is the chemical symbol of the element

      Z ←-------------- This subscript is the atomic number of isotope

In our case, the notiation for the isotope of silicon is:  ²⁸₁₄ Si

So, we have:

  • 28 is the mass number (A)
  • 14 is the atomic number (Z)
  • Si is the chemical symbol.

Now, you can answer the questions of the <em>part A</em>:

  • Number of protons: Z = 14
  • Number of neutrons N:

       mass number = number of protons + number of neutrons

                   A         =                 Z              +                N

⇒ N = A - Z = 28 - 14 = 14

In <u>conclusion</u>:

  • Number of protons, Z = 14
  • Number of neutrons, N = 14
5 0
3 years ago
For question numbers 1 and 2, two statements are given - one labelled
Svetllana [295]

Answer:

(iv) (A) is false, but (R) is true.

Explanation:

It is not true that carbon has a strong tendency to either lose or gain electrons to attain noble gas configuration. Carbon is a member of group 14, it is the first member of the group and carbon is purely a non metal. Only metals metals can loose electrons to attain the noble gas configuration. Moreover, carbon does not participate in ionic bonding so it does not gain electrons to attain the noble gas configuration.

However, carbon participates in covalent bonding where it is covalently bonded to four other chemical species using its four outermost electrons. Carbon forms covalent bonds in which four electrons are shared with other chemical species.

5 0
3 years ago
Select all that apply. which of the following are density labels? kg/l g/m g/ml cm^3/g
Strike441 [17]
I would say that only the only density label is cm^3/g
4 0
3 years ago
Read 2 more answers
1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is
earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

\frac{6}{80}=\frac{V_{2} }{40}

V_{2}=\frac{6*40}{80}=3 L

So, 3 L will be the final volume for the gas as per Charle's law.

4 0
3 years ago
11. What is the concentration (in M) of an ammonia (NH3) solution if 12.23 grams of ammonia are
photoshop1234 [79]

Answer:  1.284M NH3

Explanation:  (12.23 grams)/(17.0 gramms/mole) = 0.7191 moles

Dissolved in 560.0 ml (=0.5600L)

(0.7191 moles)/(0.560L) = 1.284M  (4 sig figs)

5 0
3 years ago
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