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Serjik [45]
3 years ago
8

When light reaches a barrier or the edge of an opening it diffracts, which means that the light _________. A) bends. B) bounces

back. C) continues in the same direction. D) is unable to continue traveling.
Physics
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

a

Explanation:

rusak2 [61]3 years ago
3 0
A. it bends when light reaches an end of a barrier it will bend.
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800 joules of work were done with a force of 200 newtons. Over what
Svetach [21]

Answer:

4m

Explanation:

800/200

7 0
3 years ago
A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6
stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

|d S|=\sqrt{d S^{2}}

&

d S=r_{2}-r_{1}

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

v_{a v g}=\frac{|\mathrm{d} S|}{d T}

v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}

As dT=7.2 sec

Now,

Solving the equation, we get;

v(a v g)=\frac{5.390732789}{7.2}

\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0
3 years ago
Help please !! physics kinematic equations
jarptica [38.1K]

Explanation:

A or E I think cous I use to do this in yr 7

7 0
3 years ago
14. How long will it take for the boat to cross the river?
erica [24]

Answer:

D

Explanation:

3 0
3 years ago
An astronaut is on a new planet. She discovers that is she drops a space rock from 12m above the groundnut has a final velocity
RUDIKE [14]

Answer:

-0.375 m/s2

Explanation:

To find the acceleration due to gravity in this planet, we can use the Torricelli formula of UALM (uniformly accelerated linear motion):

V^2 = Vo^2 + 2*a*S

Where V is the final velocity, Vo is the inicial velocity, a is the acceleration and S is the total displacement.

With V = 3, Vo = 0 and S = -12, we have:

3^2 = 0^2 - 2*a*12

24a = -9

a = -9/24 = -0.375 m/s2

7 0
3 years ago
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