Answer:
11.9g remains after 48.2 days
Explanation:
All isotope decay follows the equation:
ln [A] = -kt + ln [A]₀
<em>Where [A] is actual amount of the isotope after time t, k is decay constant and [A]₀ the initial amount of the isotope</em>
We can find k from half-life as follows:
k = ln 2 / Half-Life
k = ln2 / 27.7 days
k = 0.025 days⁻¹
t = 48.2 days
[A] = ?
[A]₀ = 39.7mg
ln [A] = -0.025 days⁻¹*48.2 days + ln [39.7mg]
ln[A] = 2.476
[A] = 11.9g remains after 48.2 days
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We'll look at what happens<span> when you </span>dissolve ionic<span> and covalent </span>compounds<span> in </span>water<span>. </span>Ionic compounds<span> break apart into the </span>ions<span> that make them up, a process called dissociation, while covalent </span>compounds only break into the molecules, not the individual atoms.<span>When you immerse an </span>ionic compound<span> in </span>water<span>, the ions are attracted to the </span>water <span>molecules, each of which carries a polar charge. If the attraction between the ions and the </span>water <span>molecules </span>is<span> great enough to break the bonds holding the ions together, the compound </span><span>dissolves</span>
Which list of elements contains two metalloids?(1) Si, Ge, Po, Pb (3) Si, P, S, Cl(2) As, Bi, Br, Kr (4) Po, Sb, I, Xe
jeka94
The answer is (1). Si and Ge are both metalloids (semimetals)
Answer:
Pi = 0.25[P(TTL)/n(TTL)]
Explanation:
Let Total Pressure = P(TTL) and Total moles =n(TTL) => n(i)/n(TTL) = P(i)/P(TTL)
Given n(i) = 0.25 => Pi = 0.25[P(TTL)/n(TTL)]
