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Hitman42 [59]
3 years ago
10

A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m

/s (relative to the ground) and then catches the ball after it rebounds from the wall. How fast is he moving after he catches the ball? Ignore the projectile motion of the ball, and assume that it loses no energy in its collision with the wall. Answer in units of m/s.
Physics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

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morpeh [17]

Given :

Mass =5kg

T

1

=20

∘

C,T

2

=100

∘

C

ΔT=100−20=80

∘

C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

6 0
3 years ago
A hydraulic car jack needs to be designed so it can lift a 2903.57 lb car assuming that a person can exert a force of 24.41 lbs.
marishachu [46]

Answer:

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

Let F_{1} = 2903.57 lb, F_{2} = 24.41 lbs, r_{2} = 3.26 cm = 0.0326 m.

A_{2} = \pi r^{2}

    = \frac{22}{7} x (0.0326)^{2}

    = 0.00334 m^{2}

So that:

\frac{2903.57}{A_{1} } = \frac{24.41}{0.00334}

A_{1} = \frac{2903.57*0.00334}{24.41}

    = 0.3973

A_{1} = 0.4 m^{2}

The radius of the piston can be determined by:

A_{1} = \pi r^{2}

0.3973 = \frac{22}{7} x r^{2}

r^{2} = \frac{0.3973*7}{22}

   = 0.1264

r = \sqrt{0.1264}

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).

4 0
2 years ago
A long uniform wooden board (a playground see-saw) has a pivot point at its center. An older child of mass M=32 kg is sitting a
PIT_PIT [208]

Answer:\frac{5L}{6}

Explanation:

Given

Wooden board is pivoted at center and

Older child of mass M=32\ kg is sitting at a distance of L from  center

if two child of mass \frac{M}{2} is sitting at a distance \frac{L}{6} and x(say) from pivot then net torque about pivot is zero

i.e.

\Rightarrow \tau_{net}=MgL-\frac{M}{2}g\frac{L}{6}-\frac{M}{2}gx

as \tau_{net}=0

Therefore

MgL=\frac{M}{2}g\frac{L}{6}+\frac{M}{2}gx

L-\frac{L}{6}=x

x=\frac{5L}{6}

Therefore another child is sitting at a distance of \frac{5L}{6}

3 0
3 years ago
What is the value of acceleration of a body if it is in uniform velocity​
Eddi Din [679]

Answer:

Zero

Explanation:

The acceleration of body moving with uniform velocity is zero, because there is no change in velocity.

5 0
2 years ago
In " m a x f o r t e d u c a t i o n " . what is probability of vowels.​
LiRa [457]

Answer:

7/16 <em>is </em><em>the </em><em>probability </em><em>of </em><em>given </em><em>querty</em>

8 0
2 years ago
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