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Dimas [21]
3 years ago
13

Opinion: Choose a side and defend it in four to five sentences. Given the choice between a vehicle that runs on gasoline or one

that runs on electricity such as the Aptera 2e, which would you choose and why? Think about fuel consumption, design of the vehicles, and other factors that may influence your decision.
Engineering
2 answers:
vaieri [72.5K]3 years ago
6 0

Answer:

my opinion would be electric

Explanation:

because when it comes down to the bare minimum the best choice for the world in the long run would be electric because it puts a big dent back for global warming and the burning of gasses so the more people who drive electric cars are the people who are trying to save the world a little at a time by preventing the burning of gasses. hope this helps :)

IRISSAK [1]3 years ago
6 0
I would say electric
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<h3><u>CSMA/CD Protocol: </u></h3>

Carrier sensing can transmit the data at anytime only the condition is before sending the data sense carrier if the carrier is free then send the data.

But the problem is the standing at one end of channel, we can’t send the entire carrier. Because of this 2 stations can transmit the data (use the channel) at the same time resulting in collisions.

There are no acknowledgement to detect collisions, It's stations responsibility to detect whether its data is falling into collisions or not.

<u>Example: </u>

T_{P}=1 H r, at time t = 10.00 AM, A starts, 10:59:59 AM B starts at time 11:00 AM collision starts.

12:00 AM A will see collisions

Pocket Size to detect the collision.

\begin{aligned}&T_{t} \geq 2 T_{P}\\&\frac{L}{B} \geq 2 T_{P}\\&L \geq 2 \times T_{P} \times B\end{aligned}

CSMA/CD is widely used in Ethernet.

<u>Efficiency of CSMA/CD:</u>

  • In the previous example we have seen that in worst case 2 T_{P} time require to detect a collision.
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We are given number of collisions (contentions slots)=4.

\text { Propagation day }=\frac{\text {distance}}{\text {speed}}

Distance = 1km = 1000m

\begin{aligned}&\text { Speed }=2 \times 10^{8} \mathrm{m} / \mathrm{sec}\\ &T_{P}=\frac{1000}{2 \times 10^{8}}=(0.5) \times 10^{-5}=5 \times 10^{-6}\\ &T_{t}=5 \mu \mathrm{sec}\end{aligned}

7 0
3 years ago
section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw
nika2105 [10]

Answer:

1. James will attack by generating a random private key XD and a corresponding public key YD.

2. Jane transmit YA to another person called Alex.

3. James intercept YA and transmit YD to jane.

4. Jane receive YD and calculate K1

At this point james and jane thinks they share a secret key but instead james has a secret key k1 to Jane and k2 to alex.

5. Alex transmit another key XA to alex for example.

6. James intercept and calculate k2 and vice versa.

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3 years ago
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nadezda [96]

Answer:

True

Explanation:

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