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Answer:
the final temperature of the tea is 7.39⁰C.
Explanation:
Given;
mass of the tea, m = 375 g
specific heat capacity of the tea, C = 4.184 JJ/g°C
initial temperature of the tea, t₁ = 95°C
the final temperature of the tea, t₂ = ?
Energy lost by the refrigerator, Q = 137,460 J
The energy lost by the refrigerator is given by the following formula;
-Q = mc(t₂ - t₁)
-137,460 =375 x 4.184(t₂ - 95°C)
-137,460 = 1569(t₂ - 95°C)
Therefore, the final temperature of the tea is 7.39⁰C.
Answer:
Explanation:
We have here values from SI and English Units. I will convert the units to English Units.
We hace for the power P,
we have other values such and
(specific weight of the water), and 0.85 for \eta
We need to figure the flow rate of the water (V) out, that is,
Where is the turbine efficiency, at which is,
Replacing,
With this value (the target of this question) we can also calculate the mass flow rate of the waters,
through the density and the flow rate,
converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,