Answer:
6.69 moles
Explanation:
Data obtained from the question include:
Volume = 2230mL
Molarity of NaOH = 3 M
First, we'll convert 2230mL to L. This is illustrated below:
1000mL = 1L
2230mL = 2230/1000 = 2.23L
Now, we can obtain the number of mole of NaOH in the solution as follow:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole of NaOH = 3 x 2.23
Mole of NaOH = 6.69 moles
Therefore, the total number of mole of the solute (NaOH) in the solution is 6.69 moles
B.
its the only one with ozone in the reaction O₃
It would be MnSO4
The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge
These will cancel out making it plain MnSO4
If it was manganese (iii) sulfide the answer would be Mn2(SO4)3
Answer:
atoms
Explanation:
Given that,
Given mass = 13200 g
Molar mass of potassium = 39.0983 g/mol
Let there are n number of moles. It is equal to mass divided by molar mass. It is equal to :
![n=\dfrac{13200}{39.0983 }\\\\=337.61\ \text{mol}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B13200%7D%7B39.0983%20%7D%5C%5C%5C%5C%3D337.61%5C%20%5Ctext%7Bmol%7D)
Let there are x atoms in 13200 g of potassium (k). It can be calculated :
![x=n\times N_A\\\\=337.61\times 6.023\times 10^{23}\\\\=20.33\times 10^{26}](https://tex.z-dn.net/?f=x%3Dn%5Ctimes%20N_A%5C%5C%5C%5C%3D337.61%5Ctimes%206.023%5Ctimes%2010%5E%7B23%7D%5C%5C%5C%5C%3D20.33%5Ctimes%2010%5E%7B26%7D)
So, there are
atoms.