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lubasha [3.4K]
4 years ago
12

Pumice is a lightweight rock that sometimes forms when lava is very rich in _____.

Chemistry
2 answers:
Oksi-84 [34.3K]4 years ago
3 0
Answer: gases

(has bubbles in the rock)
tatuchka [14]4 years ago
3 0

This question is incomplete. Here is the complete question:

Pumice is a lightweight rock that sometimes forms when lava is very rich in _____. A. silica B. gases C. feldspar D. volcanic glass

Answer:

The correct answer is option D. volcanic glass.

Explanation:

Pumice stone is a very common stone used for construction or cleaning among other things.

This rock is formed through lava that contains water and gas and comes from the inside of a volcano, so when this lava is thrown out of the volcano it cools and hardens, and is filled with bubbles of volcanic gas.

This type of rock is low density and can float on water.

Given this information we can say that the correct answer is the option D. volcanic glass

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The attractive force that holds atoms or ions together is called mixture . True or false
Masteriza [31]

Answer:

False

Explanation:

The attractive force that holds atoms or ions together is called chemical bond.

4 0
3 years ago
Describe the sunlight and length of day at the start of winter *NO GO OG LE* will give brainliest
natta225 [31]

Answer:

Although the daytime length at the Equator remains 12 hours in all seasons, the duration at all other latitudes varies with the seasons. During the winter, daytime lasts shorter than 12 hours; during the summer, it lasts longer than 12 hours.

Explanation:

Maybe this answer is hopeful in your homework.

7 0
3 years ago
A. 207 kJ<br> B. 4730 kJ<br> C. 9460 kJ<br> D. 414 kJ
MrMuchimi

Answer:

Q = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

6 0
3 years ago
What is the chemical symbol for magnesium
svp [43]
The chemical symbol for magnesium is MG
7 0
3 years ago
Read 2 more answers
How much energy (heat) is required to convert 248 g of water from 0oC to 154oC? Assume that the water begins as a liquid, that t
Arturiano [62]

<u>Answer:</u> The amount of heat required is 775.7 kJ

<u>Explanation:</u>

The processes involved in the given problem are:  

1.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\2.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(100^oC,373K)\\3.)H_2O(l)(100^oC,373K)\rightarrow H_2O(g)(100^oC,373K)\\4.)H_2O(g)(100^oC,373K)\rightarrow H_2O(g)(154^oC,427K)

Now, we calculate the amount of heat released or absorbed in all the processes.

  • <u>For process 1:</u>

q_1=m\times L_f

where,

q_1 = amount of heat absorbed = ?

m = mass of water or ice = 248 g

L_f = latent heat of fusion = 334 J/g

Putting all the values in above equation, we get:

q_1=248g\times 334J/g=84832J

  • <u>For process 2:</u>

q_2=m\times C_{p,l}\times (T_{2}-T_{1})

where,

q_2 = amount of heat absorbed = ?

C_{p,l} = specific heat of water = 4.184 J/g°C

m = mass of water = 248 g

T_2 = final temperature = 100^oC

T_1 = initial temperature = 0^oC

Putting all the values in above equation, we get:

q_2=248g\times 4.184J/g^oC\times (100-0)^oC=103763.2J

  • <u>For process 3:</u>

q_3=m\times L_v

where,

q_3 = amount of heat absorbed = ?

m = mass of water or ice = 248 g

L_v = latent heat of vaporization = 40.79kJ/mol\times \frac{1000}{18}=2266.1J/g      (Conversion factor used:  1 kJ = 1000 J and molar mass of water = 18 g/mol)

Putting all the values in above equation, we get:

q_3=248g\times 2260J/g=560480J

  • <u>For process 4:</u>

q_4=m\times C_{p,g}\times (T_{2}-T_{1})

where,

q_4 = amount of heat absorbed = ?

C_{p,g} = specific heat of steam = 1.99 J/g°C

m = mass of water = 248 g

T_2 = final temperature = 154^oC

T_1 = initial temperature = 100^oC

Putting all the values in above equation, we get:

q_4=248g\times 1.99J/g^oC\times (154-100)^oC=26650.1J

Calculating the total heat absorbed, we get:

Q=q_1+q_2+q_3+q_4

Q=[84832+103763.2+560480+26650.1]J=775,725.3J=775.7kJ

Hence, the amount of heat required is 775.7 kJ

5 0
4 years ago
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