Question

Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas.Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

Answer 1

Answer:

Explanation:

From the statement of the problem,

  B₂S₃$_{s}$ + H₂O$_{l}$  →  H₃BO₃$_{aq}$ + H₂S$_{g}$

              B₂S₃ + H₂O  →  H₃BO₃ + H₂S

We that the above expression does not conform with the law of conservation of mass:

To obey the law, we need to derive a balanced reaction equation:

   Let us use the mathematical method to obtain a balanced equation.

let the balanced equation be:

                        aB₂S₃ + bH₂O  →  cH₃BO₃ + dH₂S

where a, b, c and d will make the equation balanced.

  Conservating B: 2a = c

                          S: 3a = d

                          H: 2b = 3c + 2d

                           O: b = 3c

   if a = 1,

      c = 2,

      b = 6,

      2d = 2(6) - 3(2) = 6, d = 3

Now we can input this into our equation:

                     B₂S₃ + 6H₂O  →  2H₃BO₃ + 3H₂S

    B₂S₃$_{s}$ + 6H₂O$_{l}$  →  2H₃BO₃$_{aq}$ + 3H₂S$_{g}$