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r-ruslan [8.4K]
3 years ago
15

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

uet exerts a force of 540 N on the ball for 5.00 ms, giving it a final velocity of 45.0 m/s. Using these data, find the mass (in grams) of the ball.
Physics
1 answer:
never [62]3 years ago
7 0

Answer:

60 grams

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

m = Mass

F = Force

Impulse

J=Ft

J=m(v-u)\\\Rightarrow Ft=m(v-u)\\\Rightarrow m=\frac{Ft}{v-u}\\\Rightarrow m=\frac{540\times 5\times 10^{-3}}{45-0}\\\Rightarrow m=0.06\ kg=60\ g

Mass of the tennis ball is 60 grams

or

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{45-0}{0.005}\\\Rightarrow a=9000\ m/s^2

F=ma\\\Rightarrow m=\frac{F}{a}\\\Rightarrow m=\frac{540}{9000}\\\Rightarrow m=60\ grams

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A box (m = 20 kg) is sliding on a horizontal surface. it is connected to a massless hook by a light string passing over a massle
Varvara68 [4.7K]

mass of the box = 20 kg

force of friction on the box due to surface

F_s = \mu_s N

F_s = 0.80 * 20 * 9.8

F_s = 156.8 N

similarly kinetic friction on it

F_k = \mu_k N

F_k = 0.30* 20 * 9.8

F_k = 58.8 N

now the weight of the suspended block will be

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so here the weight of the suspended block is less than the limiting friction on it

So here we will say that friction will counter balance the weight of the suspended block and it will not move at all

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5 0
4 years ago
In a 5000 m race, the athletes run 12 1/2 laps; each lap is 400 m.Kara runs the race at a constant pace and finishes in 17.9 min
Ksju [112]

Answer:

No. of laps of Hannah are 7 (approx).

Solution:

According to the question:

The total distance to be covered, D = 5000 m

The distance for each lap, x = 400 m

Time taken by Kara, t_{K} = 17.9 min = 17.9\times 60 = 1074 s

Time taken by Hannah, t_{H} = 15.3 min = 15.3\times 60 = 918 s

Now, the speed of Kara and Hannah can be calculated respectively as:

v_{K} = \frac{D}{t_{K}} = \frac{5000}{1074} = 4.65 m/s

v_{H} = \frac{D}{t_{H}} = \frac{5000}{918} = 5.45 m/s

Time taken in each lap is given by:

(v_{H} - v_{K})t = x

(5.45 - 4.65)\times t = 400

t = \frac{400}{0.8}

t = 500 s

So, Distance covered by Hannah in 't' sec is given by:

d_{H} = v_{H}\times t

d_{H} = 5.45\times 500 = 2725 m

No. of laps taken by Hannah when she passes Kara:

n_{H} = \frac{d_{H}}{x}

n_{H} = \frac{2725}{400} = 6.8 ≈ 7 laps

3 0
3 years ago
A person applies a rightward force of 80 N to a cart of physics textbooks what is the reaction force
Goryan [66]

Just as Prof. Newton said: "For every action, there is an EQUAL, OPPOSITE reaction.". (See his motion law #3.)

If our person APPLIED a force of 80N pointing to the right, then that's the 'action'.  It must follow, as the night follows the day, that the strength of the equal REaction is also 80N, and it points to the left because it's opposite to the action.    

6 0
3 years ago
You are on an airplane traveling 30° south of due west at 180 m/s with respect to the air. The air is moving with a speed 31 m/s
BlackZzzverrR [31]
1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>
6 0
4 years ago
A block of mass m 5.00 kg is
vekshin1
<span>a.
the force in the direction of movement
Fx = F x cosA*
Fx = 12 x cos25*
Fx = 10.88
m x a = 10.88
a = 10.88/5
a= 2.18 m/s^2
b.
when the block will be lifted off the floor and when the vertical component
Fy = mg
Fy = F x sin25*
Fy= 5 x 9.8
Fy= 115.94 N
c.
if Fx = ma
a = 115.94/5
a= 23.19 m/s^2
hope it helps
</span>
6 0
3 years ago
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