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devlian [24]
3 years ago
7

1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium

Chemistry
1 answer:
aniked [119]3 years ago
7 0

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

M_1 =concentration of stock solution = 0.150 mol/L

V_1 = volume of stock solution = 10.0 ml

M_2 = concentration of dilute solution = ?

V_2 = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

0.150\times 10.0=M_2\times 100.0

M_2=0.015mol/L

As the concentration is less than the original concentration, the solution is termed as dilute.

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Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

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Mass of NaOH(WB)=22.9 g

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Molar mass of NaOH(MB)=23+16+1.01=40.01

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Using the formula

Number of moles of  NaOH(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}

n_B=0.572moles

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Number of moles of water(n_A)=\frac{77.1}{18.02}

n_A=4.279 moles

Now, mole fraction of NaOH

=\frac{n_B}{n_B+n_A}

=\frac{4.279}{0.572+4.279}

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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