The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.
The total distance cover in east direction is=100*3=300 km
The total distance cover in the west direction=80*1.5=120 km
The total distance covered is =300+120=420 km
And Total displacement of the car is =300-120=180 km
As we know that the average speed is given as
Avg Speed =Total Distance / Total time
=420/4.5=93.33 km/hr
As we know that the average velocity is given as
Avg Speed =Total Displacement/ Total time
=180/4.5=40 km/hr
Therefore, The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.
Answer:
The acceleration of the body, a = 2193 m/s²
Explanation:
Given,
The mass of the body, m = 0.3 kg
The force acting on the body, F = 657.9 N
The force acting on an object is proportional to the product of mass and acceleration of the body.
F = m x a
Therefore, the acceleration of the body is
a = F / m
= 657.9 N / 0.3 kg
= 2193 m/s²
Hence, the acceleration of the body, a = 2193 m/s²
Ans; see attached file for calculation and answer
Explanation:
The average speed is 20.8 m/s
Explanation:
The average speed for the trip is given by:
where
d is the distance covered
t is the time elapsed
For the trip in this problem, we have:
d = 187 km = 187,000 m is the distance travelled
The initial time is 10:00 pm while the arriving time is 12:30 am: this means that the time elapsed is 2.5 hours. Converting into seconds,
Therefore, the average speed for the trip is
Learn more about average speed:
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