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Tpy6a [65]
3 years ago
15

A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f

orce of 15 N?
Physics
1 answer:
deff fn [24]3 years ago
6 0
Net force acting on mass = 20 - 15 = 5N. ( subtracted cuz friction always opposes the motion i.e it always acts in direction opposite to the motion of the object). According to Newton's 2nd law of motion, F(net) = ma. a =F (net) / m = 5/10 = 0.5 m/s^2. Hope it helps :)
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This question involves the concept of the scalar product.

The magnitude of the scalar product will be "0".

<h3>SCALAR PRODUCT</h3>

The scalar product, also known as the dot product of the two vectors is given by the following formula:

A.B = |A||B|Cos\theta

where,

  • A.B = Scalar product = ?
  • |A| = Mangnitude of vector A = 1 unit
  • |B| = Magnitude of Vector B = 1 unit
  • θ = Angle between vectors = 90°

Therefore,

A.B = (1)(1)Cos90^o = (1)(1)(0)

A.B = 0

Learn more about scalar product here:

brainly.com/question/6849226

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3 years ago
[Please help fast! Offering 100 points if it works!}
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Answer:

d=1.49×1011m

Explanation:

Velocity is defined as the rate of travel, and can be found using the distance formula.

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We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.

t=(8.3minutes)(60seconds/minute)=(498s)

Now our units work out and we can solve for distance.

= 15.85

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