Given:
Object in circular motion 25 m/s
1 second to go quarter circle
Required:
Centripetal acceleration:
Solution:
Acceleration = v2/r
Where v is the velocity and r is
the radian
Substituting the values into the
equation,
Acceleration = v2/r = (25
m/s)2/(4*pi/180) = 8952.47 m2/s2
The practice of playing top hits several times a day on radio stations is called rotation.
Answer:
6 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
Acceleration is defined mathematically as:
Acceleration (a) = Velocity (v) /time (t)
a = v /t
With the above formula, we can obtain the acceleration of the object as follow:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
a= v/t
a= 30/5
a = 6 m/s²
Therefore, the acceleration of the object is 6 m/s² due East.
Since it moves 5 m/s faster every second, after 20 seconds it's moving 100 m/s faster than when it started speeding up.
If it was moving at 14 m/s when the acceleration began, it's moving at 114 m/s at the end of the 20 seconds. Its velocity is <em>114 m/s North.</em>
That's 255 mph !
Answer:
The current in the wire under the influence of the force is 216.033 A
Solution:
According to the question:
Length of the wire, l = 0.676 m
Magnetic field of the Earth, 
Forces experienced by the wire, 
Also, we know that the force in a magnetic field is given by:
I = 216.033 A
