Answer:
The bus moved after our girl Sandy passed out = S = 905.04 m
Explanation:
At t = 0 sec Vi = 80mph = 35.76 m/s
t = 30 sec Vf = 55mph = 24.58 m/s
According to the first equation of motion
<u>Vf = Vi + at</u>
24.587 = 35.76 + a(30)
a = - 0.373 m/s2 (negative sign shows deceleration)
Now for distance travelled in 30 sec we have
second equation of motion
<u> S=Vit+1/2at2</u>
S = 35.76 x 30 + 1/2 x -0.373 x 30 x 30
S = 905.04 m
I believe
the answer is C. 0.14cm.
The zero error in vernier caliper is read by the distance by which the zero of the movable part of the scale is shifted from the zero of the cm ruler in the tool, which is the unmovable part of the tool. The movable part has a scale accuracy of 0.1 cm, while the other has a scale accuracy of 1 cm. And we always use the lowest scale, which is here the 0.1 scale which has greater accuracy with 10 times the 1 cm ruler, to find our errors.
Hope this helps!
Answer:
The total distance is 105 kilometers, and the total displacement is 15 kilometers east.
Explanation:
A truck moves 60 km east and then 45 km (60 - 15) back to west. The total distance will be,
Distance = 60 + 45 = 105
Distance is a scalar quantity that refers to the total space covered by a truck (object).
Displacement is a vector whose length is the shortest distance from the initial to the final position of a point undergoing motion.
The truck moves from Point A to Point B, covers 60 km. Then the truck turns back from point B to point C, 15 km away from the point A. So the displacement will be
Displacement = 60 - 45 = 15
Displacement is the difference between point A and C.
For further understanding, see the attached picture.
Answer:
9. (B) ¼ Mv²
10. (A) √(3gL)
11. 20 N
12. 5 m/s²
Explanation:
9. The rotational kinetic energy is:
RE = ½ Iω²
RE = ½ (½ MR²) (v/R)²
RE = ¼ Mv²
10. Energy is conserved.
Initial potential energy = rotational energy
mgh = ½ Iω²
Mg(L/2) = ½ (⅓ ML²) ω²
g(L/2) = ½ (⅓ L²) ω²
gL = ⅓ L² ω²
g = ⅓ L ω²
ω² = 3g / L
ω = √(3g / L)
The velocity of the top end is:
v = ωL
v = √(3gL)
11. Sum of torques about the hinge:
∑τ = Iα
-(Mg) (L/2) + (T) (r) = 0
T = MgL / (2r)
T = (3.00 kg) (10 m/s²) (1.60 m) / (2 × 1.20 m)
T = 20 N
12. Sum of forces on the block in the -y direction:
∑F = ma
mg − T = ma
Sum of torques on the pulley:
∑τ = Iα
TR = (½ MR²) (a / R)
T = ½ Ma
Substitute:
mg − ½ Ma = ma
mg = (m + ½ M) a
a = mg / (m + ½ M)
Plug in values:
a = (3.0 kg) (10 m/s²) / (3.0 kg + ½ (6.0 kg))
a = 5 m/s²
Answer:
In chemical compounds, atoms tends to have the electron configuration of a noble gas.
Explanation:
The noble gases are unreactive because of their electron configurations. This noble gas neon has the electron configuration of 1s22s22p6 . It has a full outer shell and cannot incorporate any more electrons into the valence shell.
The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas. An exception to an octet of electrons is in the case of the first noble gas, helium, which only has two valence electrons.