After x seconds, an object will fall 

 where a is acceleration due to gravity and t is time
so when t=3.3
the distance it will fall is 

=53.361m
it will fal 53.361 meters
 
        
        
        
Answer:
20 N/m
Explanation:
From the question,
The ball-point pen obays hook's law.
From hook's law,
F = ke............................ Equation 1
Where F = Force, k = spring constant, e = compression.
Make k the subject of the equation
k = F/e........................ Equation 2
Given: F = 0.1 N, e = 0.005 m.
Substitute these values into equation 2
k = 0.1/0.005
k = 20 N/m.
Hence the spring constant of the tiny spring is 20 N/m
 
        
             
        
        
        
Answer:
 α = 2,857 10⁻⁵ ºC⁻¹
Explanation:
The thermal expansion of materials is described by the expression
           ΔL = α Lo ΔT
           α = 
in the case of the bar the expansion is
          ΔL = L_f - L₀ 
          ΔL=   1.002 -1
          ΔL = 0.002 m
the temperature variation is
          ΔT = 100 - 30
          ΔT = 70º C
we calculate
          α = 0.002 / 1 70
          α = 2,857 10⁻⁵ ºC⁻¹
 
        
             
        
        
        
Regardless of the speed of the ball or its angle, once it has left the kickers foot it's acceleration is always g downward. -9.81m/s^2
        
                    
             
        
        
        
Answer: The working and answer can be viewed from the screenshots below. Thanks