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Svet_ta [14]
3 years ago
13

What type of reaction feels cold to the touch? A. Endothermic, because energy is being released into the surroundings B. Endothe

rmic, because energy is being absorbed from the surroundings C. Exothermic, because energy is being released into the surroundings D. Exothermic, because energy is being absorbed from the surroundings
Physics
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:

D. Exothermic, because energy is being absorbed from the surroundings

Explanation:

This is true about the Exothemic reaction due to the fact that, the reaction occurs outside the body. During this reaction, the energy being absorbed <em>from the surrounding environment will hit the body surface thereby creating the coldness due to the heat given out from the body  being minimal.</em>

vlada-n [284]3 years ago
4 0

Answer:

Endothermic, because energy is being absorbed from the surroundings.

Explanation:

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How much does it take a person to walk 12km north at a velocity of 6.5 km/h?
mote1985 [20]

Answer:

1.846....hours

Explanation:

since if we divide 12 km or just 12 by 6.5 we will get this number meaning that this is how long it would take someone

4 0
3 years ago
The main difference between internal combustion engine and the diesel engine is?
Sav [38]
<span>The difference between a internal combustion engine and a diesel engine is the ignition, But a Diesel engine is an internal combustion engine. The both burn internal one uses compression to fire the other uses ignition system.</span>
8 0
3 years ago
Read 2 more answers
A parallel-plate capacitor has a plate area of 0.2m^2 and a plate separation of 0.1mm. To obtain an electric field of 2.0 × 10^6
Oduvanchick [21]

Answer:

3.536*10^-6 C

Explanation:

The magnitude of the charge is expresses as Q = CV

C is the capacitance of the capacitor

V is the voltage across the capacitor

Get the capacitance

C = ε0A/d

ε0 is the permittivity of the dielectric = 8.84 x 10-12 F/m

A is the area = 0.2m²

d is the plate separation = 0.1mm = 0.0001m

Substitute

C = 8.84 x 10-12 * 0.2/0.0001

C = 1.768 x 10-8 F

Get the potential difference V

Using the formula for Electric field intensity

E = V/d

2.0 × 10^6  = V/0.0001

V = 2.0 × 10^6  * 0.0001

V = 2.0 × 10^2V

Get the charge on each plate.

Q = CV

Q =  1.768 x 10-8 * 2.0 × 10^2

Q = 3.536*10^-6 C

Hence the magnitude of the charge on each plate should be 3.536*10^-6 C

5 0
2 years ago
While performing an experiment, the student creating the data table is not sure if a measurement from the experiment is a vector
marin [14]

Before coming into conclusion first we have to understand both scalar and vector .

A scalar quantity is a physical quantity which has only magnitude for it's complete specification.

A vector quantity is that physical quantity which not only requires magnitude but also possesses direction for it's complete specification.

So the most important factor that differentiate vector from scalar is the direction.

As per the question the student is doing an experiment where he is recording the data obtained during the process.

In order to arrange them in data table, he should ask about the direction of the quantity under consideration.


Hence the correct option is the third option(C)i.e does the measurement include direction?




7 0
3 years ago
Read 2 more answers
If the mass of both objects are doubled while the
lutik1710 [3]

Answer:

The force becomes 16 times what it is now.

Explanation:

The formula for gravitational force is

F = G * m1 * m2 / r^2

When you do what you have described, you are setting a stage that not even the USS Enterprise (Star Trek) can get out of. The increase is huge.

If you double m1 and m2 and don't do anything to r, you've already increased the force by 4 times. (2m1 * 2m2 = 4 * m1 * m2)

But you are not finished. If you 1/2 the distance, you are again increasing the Force by 4 times. 1 / (2r) ^2 = 1/ 4* r^2

Because this is in the denominator, the 1/4 is going to flip to the numerator.

So the total increase is going to be 4 * (4 * m1 * m2) = 16 * m1 * m2.

Think about what that means. If you were out golfing, your drives would be roughly 1/16 times as far as they are now. Also you would be lugging around 16 times your weight around the golf course. My feeling is that you would never finish 5 holes at that rate.

3 0
2 years ago
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