The solubilty product (Ksp) of PbCl₂ : Ksp = [Pb²⁺][Cl⁻]²
<h3>Further explanation</h3>
Given
PbCl₂ compound
Required
The solubilty product (Ksp)
Solution
Ksp is the product of ions in an equilibrium saturated state
For reaction :
AₓBₐ (s) ⇔ aAᵃ⁺ (aq) + b Bᵇ⁻ (aq)
Can be formulated :
Ksp = [Aᵃ⁺] ᵃ [Bᵇ⁻] ᵇ
For PbCl₂ :
PbCl₂(s)⇔Pb²⁺(aq) + 2Cl⁻(aq)
Ksp = [Pb²⁺][Cl⁻]²
Answer:
76.1g
Explanation:
The balanced equation for this reaction is as follows:
3NaOH + AlCl3 --> Al(OH)3 + 3NaCI
From the above equation, it can be observed that 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Using the formula below, we convert the mass of NaCl to moles;
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 100/58.5
mole = 1.71mol of NaCl
Since 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Then 1.71 moles of NaCl will be produced by 1.71/3 = 0.57mol of AlCl3
Molar mass of AlCl3 = 27 + 35.5(3)
= 27 + 106.5
= 133.5g/mol
Mole = mass/molar mass
Mass = molar mass × mole
Mass = 133.5 × 0.57
Mass = 76.1g
A) The recursive formula for the number of seats in the n th row will be;
S1 = 9
S(n) = S (n-1) +2
b) Explicit formula; is that of an arithmetic progression; such that if a is the first term , and d is the common difference , then the n th term will be given by the formula: a + (n-1) d; where a is 9, and d is 2
Hence; for n th row = 9+ 2(n-1)
c) Number of seats in 12 th row using the formula in b.
n = 12 , a = 9, d = 2
therefore; 9 + 2(12-1)
= 9 + 2(11)
= 31 seats
Answer:
the answer is static friction.
Answer:
A. Diagram B is a gas, because its particles move more slowly and are farther apart.