Answer:
86.0 mL
Explanation:
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Answer:
![\frac{4molPF_3}{1molP_4}](https://tex.z-dn.net/?f=%5Cfrac%7B4molPF_3%7D%7B1molP_4%7D)
Explanation:
Hello
In this case, given the reaction:
![P_4(s)+6F_2(g)\rightarrow 4PF_3(g)](https://tex.z-dn.net/?f=P_4%28s%29%2B6F_2%28g%29%5Crightarrow%204PF_3%28g%29)
It means that since the coefficients preceding phosphorous and phosphorous trifluoride are 1 and 4, the correct mole ratio should be:
![\frac{4molPF_3}{1molP_4}](https://tex.z-dn.net/?f=%5Cfrac%7B4molPF_3%7D%7B1molP_4%7D)
Because given the mass of phosphorous it is convenient to convert it to moles and then cancel it out with the moles on bottom of the mole ratio.
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Answer:
0.4 moles of water produced by 6.25 g of oxygen.
Explanation:
Given data:
Mass of oxygen = 6.25 g
Moles of water produced = ?
Solution:
Chemical equation;
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 6.35 g/ 32 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of oxygen with water:
O₂ : H₂O
1 : 2
0.2 : 2×0.2 = 0.4 mol
0.4 moles of water produced by 6.25 g of oxygen.
Answer:
1,081.1 units of heparin should be given to 298 lb person.
Explanation:
We are given:
Weight of the person = 298 lb = 135.143 kg
Conversion factor used:
1 lb = 0.4535 kg
Number of unit of heparin to be given in an hour = 8.0 units/kg
Number of units given to the patient weighing 135.143 kg :
![8.0 units/kg\times 135.143 kg=1,081.144 units\approx 1,081.1 units](https://tex.z-dn.net/?f=8.0%20units%2Fkg%5Ctimes%20135.143%20kg%3D1%2C081.144%20units%5Capprox%201%2C081.1%20units)
1,081.1 units of heparin should be given to 298 lb person.