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Sedaia [141]
3 years ago
13

Succinate dehydrogenase catalyzes the conversion of succinate to fumarate. The reaction is inhibited by malonic acid, which rese

mbles succinate but cannot be acted upon by succinate dehydrogenase. Increasing the ratio of succinate to malonic acid reduces the inhibitory effect of malonic acid. What is malonic acid's role with respect to succinate dehydrogenase? Malonic acid
Chemistry
1 answer:
allsm [11]3 years ago
3 0

Answer:

Here malonic acid acts as a competitive inhibitor of succinate dehydrogenase

Explanation:

Malonic acid structurally resembles succinic acid as a result the enzyme succinate dehydrogenase cannot distinguish between malonic acid and succinic acid.

      That"s why malonic acid interact with succinate dehydrogenase thereby blocking the catalytic activity of the later.

      As this mechanism is a type of competitive inhibition that"s why increasing the concentration of substrate succinic acid can reduce the inhibitory effect of malonic acid.

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Differentiate between short period and long period in modern periodic table​
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How does doubling the volume of solvent affect the concentration of the solution?
Alex17521 [72]

Answer:

Molarity is halved when the volume of solvent is doubled.

Explanation:

Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.

Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.

Plugging these numbers into the equation, we can figure out the final molarity.

(1 L)(1 M)=(2 L)(X M)

X M= (1 L x 1 M)/(2 L)

X M= 1/2 M

This shows that the molarity is halved when the volume of solvent is doubled.

8 0
3 years ago
A methanol-water mixture is to be flash distilled at 1 atm. If the feed is 25 mole %methanol, what are the liquid and vapor comp
frozen [14]

Answer:

Explanation:

Given that:

The distillation is carried out at a pressure of 1 atm

The feed harbors 25% mole of methanol (z)

The total moles of feed is usually 100 moles

In the system, we have both methanol and water

Using the total mole balance for the distillation column.

Fz = Lx + Vy

where;

F = amount of feed

z = mole fraction of ethanol (in feed)

L = amount of liquid product out of the column

V = amount of vapor product out of the column

x = mole fraction of methanol out of the liquid

y  = mole fraction of methanol out of the vapor.

SO;

(a)

If all the feed is vaporized, then the vapor will likely have the same composition as the feed.

(b)

If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.

(c)

If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.

The balance equation would be:

Fz = (\dfrac{2}{3}F) x + (\dfrac{1}{3}F)y \\ \\ z = \dfrac{2}{3}x+\dfrac{1}{3}y

Replacing z = 0.25; we have:

0.25 = \dfrac{2}{3}x+\dfrac{1}{3}y

0.75 = 2x + y

(d)

If 2/3 of the feed is vaporized;

Then:

Fz = (\dfrac{1}{3}F) x + (\dfrac{2}{3}F)y \\ \\ z = \dfrac{1}{3}x+\dfrac{2}{3}y

replacing z = 0.25

0.25 = \dfrac{1}{3}x+\dfrac{2}{3}y

0.75 = x + 2y

6 0
3 years ago
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