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Alik [6]
2 years ago
6

I need to solve for x in this equation ln(760/630)=32/8.314(1/x-1/329.5)

Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
4 0
X=0.031903 I think if you don’t know how to do this photo math would be a good thing for you
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What is the molarity of a solution in which 25.3 grams of potassium bromide is dissolved in 150. mL of solution?
irga5000 [103]

Answer:

~1.417M

Explanation:

Molarity=(number of moles of solute)/(litres of solution)

In this case, we need to find moles of potassium bromide.

Mass=25.3g

Molar mass= 119g/mol

moles=(mass/molar mass)

        =(25.3)/(119)

        =0.2126moles of potassium bromide

Molarity=(0.2126)/(150/1000)

       ~1.417M

Hope this helps:)

6 0
2 years ago
Read 2 more answers
What type of bond holds the complementary bases together?.
olga55 [171]

Answer:

hydrogen bonding

Explanation:

The two strands of DNA are held together by hydrogen bonds between complimentary nucleotides.

3 0
2 years ago
Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
Zina [86]

<u>Given:</u>

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

Iron = 7.9 g/cm3

Titanium = 4.8 g/cm3

Unknown sample mass = 9.5 g

Sample volume = 2.1 cm3

<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

Density = Mass/Volume

For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

4 0
2 years ago
60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is
Sidana [21]

Answer:

B) is the correct answer

3 0
3 years ago
A 16.0 mL sample of a 1.04 M potassium sulfate solution is mixed with 14.3 mL of a 0.880 M barium nitrate solution and this prec
stiks02 [169]
Number of moles in the K2SO4 sample
= (16/1000)*1.04= 0.01664 mol

Number of moles in the Ba(NO3)2 sample
= (14.3/1000*0.880)= 0.01258 mol

Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.

The molecular mass of BaSO4 is 137.3+(32.06+4*16.00)=233.4
Therefore the theoretical yield of Barium Sulphate is
233.4*0.01258=2.937 g
Actual yield = 2.60 g (given)
Therefore the percentage yield = 2.60/2.937=88.54%

Answer: 
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%

I apologize for the mistake previous to this update.

5 0
2 years ago
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