Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
Answer:
GAY-LUSSAC'S LAW.
Explanation:
P1 = 765 torr
T1 = 23°C = 296K
P2 = 560. torr
T2 = ?
(765 torr)/(296K) = (560. torr)/ T2
T2 = 226 K = -57°C
Answer:
Explanation:
so if the reaction is C2H4+3O2-->2H2O+2CO2
if there were 7 moles of C2H4:
(see the attachment)
Boils
Celsius is based on the freezing and boiling points of water.
Water freezes below 0 degrees Celsius (32 degrees Fahrenheit), and it boils above 100 degrees Celsius (212 degrees Fahrenheit).
