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Pie
3 years ago
9

Superman's laser eyes have a wavelength of 6.4*10^-12, how much energy do those eyes release?

Physics
1 answer:
likoan [24]3 years ago
5 0

quite a lot :0

I hope this helps, and keep some kryptonite on hand dude!

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The temperature of a sample of water increases from 20°c to 46.6°c as it absorbs 5650 calories of heat what is the mass of the s
kompoz [17]
M=energy transferred/ (temperature change*specific heat) M= 5650/(26.6*1.0) M=212g
4 0
3 years ago
The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
ch4aika [34]

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

7 0
3 years ago
Which should not be a part of scientific inquiry?
lisabon 2012 [21]

I would say;

a - bias.

8 0
3 years ago
Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp
slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

Q=Av

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

Q=1.20 m^3/s

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2

So we can re-arrange the equation to find the speed of the water:

v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

Q_1 = Q_2\\A_1 v_1 = A_2 v_2

where we have

A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s

and where A_2 is the cross-sectional area of the pipe at the second point.

Solving for A2,

A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2

And finally we can find the radius of the pipe at that point:

A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m

6 0
3 years ago
Why are there variations of traits within a population?
nydimaria [60]

Answer:

The variation and distribution of traits in a population depend on genetic and environmental factors. Genetic variation can result from mutations caused by environmental factors or errors in DNA replication, or from chromosomes swapping sections during meiosis.

Explanation:

Hope this helps!

3 0
3 years ago
Read 2 more answers
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