Answer:
The voltage induced in the coil is 1.25 V.
Explanation:
Given;
number of turns, N = 100 turns
cross sectional area of the copper coil, A = 0.1 m²
initial magnetic field, B₁ = 0.5 T
final magnetic field, B₂ = 1.00 T
duration of change in magnetic field, dt = 4 s
The induced emf in the coil is calculated as;
Therefore, the voltage induced in the coil is 1.25 V.
Answer:
n = 4.35 x 10¹⁹
Explanation:
Given that
Voltage V= 12 V
Power rating of headlights = 41.8 W
We know that headlights of the car is connected in parallel connection.
We know that
Power = Current x Voltage
P = V I
I=3.48 A
Therefore the total current will be
I'= 3.48 + 3.48 A
I = 6.96 A
We know that
Charge = Current x time
q= I' t
q= 6.96 x 1
q= 6.96 C
The charge on electron ,e= 1.6 x 10⁻¹⁹
q= n e
n=Number of electron
n = 4.35 x 10¹⁹