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3 years ago

I need the answer pleaseee

Chemistry

1 answer:

Setler [38]3 years ago

7 0

Solids have a definite,fixed shape.. So option B which is the second checkbox ☑️ is the correct answer... l hope it helped :)

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Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.

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1)
HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻

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3 years ago

When you jump-starts a car, what happens to the stored energy in the working battery? PLEASE ANSWER

Yuri [45]

The stored energy in the battery does not work anymore.

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3 years ago

Which elements usually lose their valence electrons when they bond

masya89 [10]

Metals, for example Cesium and Francium

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3 years ago

Read 2 more answers

A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?

Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

$\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles$

Now we have to calculate the moles of $Br_2$

${\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles$

${\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles$

The balanced chemical reaction is,

$2Na(s)+Br_2(g)\rightarrow 2NaBr$

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium bromide

Now we have to calculate the percent yield of reaction

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%$

Therefore, the percent yield is, 93.4%

3 0

3 years ago

A sample of a compound contains 0.300 mol of carbon and 1.20 mol of hydrogen. What is the empirical formula of the comp

Margarita [4]

Answer:

CH4

Explanation:

The number of moles of carbon and hydrogen has been given as follows:

C = 0.300 mol

H = 1.20 mol

Next, we divide each mole value by the smallest (0.300)

C = 0.300 ÷ 0.300 = 1

H = 1.20 ÷ 0.300 = 4

The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4

3 0

3 years ago