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2 years ago

The __________ energy in food is changed into mechanical energy by your muscles.

Physics

1 answer:

Orlov [11]2 years ago

8 0

Potential energy which is the stored energy an object has waiting to be used

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A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w

Scilla [17]

Answer:

$v_f = 20 m/s$

Explanation:

Since the hoop is rolling on the floor so its total kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2} I\omega^2$

now for pure rolling condition we will have

$v = R\omega$

also we have

$I = mR^2$

now we will have

$KE = \frac{1}{2}mv^2 + \frac{1}{2}(mR^2)\frac{v^2}{R^2}$

$KE = mv^2$

now by work energy theorem we can say

$W = KE_f - KE_i$

$842 J = mv_f^2 - mv_i^2$

$842 = 3(v_f^2) - 3\times 11^2$

now solve for final speed

$v_f = 20 m/s$

3 0

2 years ago

You are driving at 40 miles per hour and you speed up to 60 miles per hour over the course of 20 miles. How long were

notka56 [123]

Answer:

120 hours

Explanation:

4 0

2 years ago

Please help i’ll mark you

suter [353]

Answer:

What should I do. reply quickly for a quick answer

8 0

1 year ago

Read 2 more answers

The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitt

nevsk [136]

Answer:3.87*10^-4

Explanation:

What is the decrease in mass, delta mass Xe , of the xenon nucleus as a result of this deca

We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.

C=f*lambda

3*10^8=f*3.44*10^-12

F=0.87*10^20 hz

Then with the frequency, find the energy emitted using equation

E=hf E = freq*Plank's constant

E=.87*10^20*6.62*10^-34

E=575.94*10^(-16)

With this energy, convert into MeV from joules.

With the energy in MeV, use E=mc^2 using c^2 = 931.5 MeV/u.

Plugging and computing all necessary numbers gives you

3.87*10^-4 u.

6 0

2 years ago

Suppose that during any period of ¼ second there is one instant at which the crests or troughs of component waves are exactly in

kolezko [41]

<h3>Answer;</h3>

A. 4

<h3>Explanation;</h3>

The period of a wave or periodic time is the time taken for a complete oscillation to occur. For example its is the time taken between two successive crests or troughs.
The beats or oscillation that occur in one second represents the frequency. Frequency is the number of complete oscillations or beats in one second in a wave.
Frequency, measured in Hertz is given by the reciprocal of the periodic time.
Thus; Frequency or beats per second = 1/(1/4) = 4
Hence , 4 beats per second

6 0

2 years ago