1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Airida [17]
3 years ago
6

An eagle flew for 3 hours at 115 km/h and 5 hours at 136 km/h. How far did the eagle fly?

Physics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

the eagle flew 1,025 km

Explanation:

since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.

You might be interested in
The time constant for RC circuit with the values of R1 and C1 is 5ms. What will be the time constant for a new RC circuit with t
lions [1.4K]

Answer:

d. 25 ms

Explanation:

  • In a RC circuit we call time constant to the product of the resistance times the capacitance, which represents the time when the charge reaches to the 63% of the final value, as follows:

       \tau_{1} = R_{1} *C_{1}  = 5 ms (1)

  • If we have a new circuit with new values for R and C, the time constant will be defined in the same way, as follows:

       \tau_{2} =10* R_{1} *0.5*C_{1}  = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)

6 0
3 years ago
A 125kg bumper car going 18.5 m/a bumps a 187.kkg bumper car at rest. if the first car (125kg) bounces back at 8 m/s what is the
kozerog [31]
  <span><span>Imagine we have a 2 lb ball of putty moving with a speed of 5 mph striking and sticking to a 18 lb bowling ball at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v1. To find v1, use momentum conservation: 2x5=(18+2)v1, v1=0.5 mph. </span><span>Next, imagine we have a 18 lb bowling ball moving with a speed of 5 mph striking and sticking to a 2 lb ball of putty at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v2. To find v2, use momentum conservation: 18x5=(18+2)v2, v2=4.5 mph. </span><span>
</span><span>
</span><span>now figure out your problem its really easy let me know if you need more help  </span></span>
3 0
3 years ago
Zoey ran a total of 1000m. 20 seconds into her run she had traveled 100 meters. What was her speed at 100 meters?
leva [86]
Let's assume that Zoey ran at a constant speed. we can use the equation,
 d = st
where, d = distance, s = speed, and t = time taken.

By rearranging,
 s = d/t
Zoey had travelled 100 m in 20 seconds.
Hence, s = 100 m / 20 s = 5 m/s

therefore Zoey's speed at 100 m is 5 m/s
7 0
3 years ago
6. A warehouse employee is pushing a 15.0 kg desk across a floor at a constant speed of 0.50 m/s. How much work must the employe
MariettaO [177]

Answer:

7.5 J

Explanation:

To answer the question given above, we need to determine the energy that will bring about the speed of 1 m/s. This can be obtained as follow:

Mass (m) = 15 Kg

Velocity (v) = 1 m/s

Energy (E) =?

E = ½mv²

E = ½ × 15 × 1²

E = ½ × 15 × 1

E = ½ × 15

E = 7.5 J

Therefore, to change the speed to 1 m/s, the employee must do a work of 7.5 J.

3 0
2 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an
a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, \mu=6\times 10^{-2}

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

KE=PE+W

\dfrac{1}{2}mv^2=mgh+W

W is the work done by the friction.

W=f\times d

f=\mu mg\ cos\theta

W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}

W=\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}

\dfrac{1}{2}v^2=9.8\times 3.1+\dfrac{6\times 10^{-2}\times 9.8\times 3.1}{tan(30)}

v = 8.19 m/s

So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0
3 years ago
Other questions:
  • The following table lists the work functions of a few commonmetals, measured in electron volts.
    14·1 answer
  • How many kisses is 50 hectokisses?<br><br> What would you be if you earn a megabuck year?
    5·2 answers
  • Type a nerve fibers in humans can conduct nerve impulses at speeds up to 140 m/s. (a) how fast are the nerve impulses in miles p
    9·1 answer
  • At summer camp, the swimming course runs the length (L) of a small lake. To determine the length of the course, the camp counsel
    11·1 answer
  • Why would a flat sheet of paper and a wad of paper with the same mass not fall through the air at the same rate?
    11·2 answers
  • Soil conservation involves protecting _______ and preventing _______.
    9·2 answers
  • Which of the following is the most likely end for a star that is small to average in size? A. blue main sequence B. red supergia
    5·2 answers
  • How much heat energy is required to raise the temperature of 0.368kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of cop
    13·2 answers
  • Models are frequently used in science to assist in the understanding of complex information. Models can include items like a wor
    7·1 answer
  • Energy of fossil fuels is also derieved from solar energy​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!