This reaction is known as
Acidic Cleavage of Ether.
Ether when treated with strong acid like
HI, the oxygen atom of ether picks the proton making a positive charge on oxygen. The
Iodide conjugate base formed acts as a
nucleophile and attacks on the carbon next to positive oxygen and forms
Alkyl Halide. This is a type of
SN² reaction. The complete reaction with missing atoms, charges and arrows is shown below,
Answer: C. <em><u>She should decrease the frequency of the wave</u></em>
<em>Explanation: this makes the waves shorter causing it to become louder the the human ear!</em>
<h3><u><em>hope it helps</em></u></h3>
Answer:
The volume would be; 136.17 ml
Explanation:
Volume V1 = 150 mL
Temperature T1 = 20°C + 273 = 293 K
Pressure P1 = 758 - 17.54 = 740.46 torr
At STP;
Volume V2 = ?
Pressure P2 = 760 torr
Temperature T2 = 273 K
Using the general gas equation;
P1V1 / T1 = P2V2 / T2
Making V2 subject of formulae;
V2 = P1V1T2 / T1P2
Inserting the values we have;
V2 = 740.46 * 150 * 273 / 293 * 760
V2 = 136.17 ml
Hey there!
1 mole has 6.022 x 10²³ atoms.
Multiply that by 3.2 because we have 3.2 moles.
3.2 x 6.022 x 10²³
1.9 x 10²⁴
There are 1.9 x 10²⁴ atoms in 3.2 moles of chromium.
Hope this helps!
Answer:
You cannot make observations if you are 57 seconds late into the lab.
Explanation:
The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.
Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.
The half life equation is;
N_t = N₀(½)^(t/t_½)
Where:
t = duration of decay
t_½ = half-life
N₀ = number of radioactive atoms initially
N_t = number of radioactive atoms remaining after decay over time t
We are given;
t = 57 secs
N₀ = 100 g
Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2
Thus;
N_t = 100(1/2)^(57/7.2)
N_t = 0.4139g
We are told that In order to make observations, you require at least .5g of material.
The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.
