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2 years ago

10

A guitar string with a linear mass density of 2.0 g/m is stretched between two vertical rods that are 65 cm apart. The string ho

lds a standing wave, fixed at both ends, with three antinodes when it oscillates at a frequency of 430 HzWhat is the frequency of the fifth harmonic of this string?

1 answer:

Rudiy272 years ago

7 0

Answer:

717 Hz

Explanation:

<u>solution:</u>

The wave with three antinodes has m = 3. Thus, f_3 = 3f_1 and so the fundamental frequency of the string is

f_1 =f_3/3

=430 Hz/3

=143 Hz

Thus, the frequency of the fifth harmonic is

f_5 = 5*f_1

= 5*143 Hz

= 717 Hz

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The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

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