It's mass and its age.
About how long will a 2-M star live as a main-sequence star.
1 billion years.
<span>A low mass red giant star's energy comes from.</span>
Answer:
76969.29 W
Explanation:
Applying,
P = F×v............. Equation 1
Where P = Power, F = force, v = velocity
But,
F = ma.......... Equation 2
Where m = mass, a = acceleration
Also,
a = (v-u)/t......... Equation 3
Given: u = 0 m/s ( from rest), v = 12.87 m/s, t = 3.47 s
Substitute these values into equation 3
a = (12.87-0)/3.47
a = 3.71 m/s²
Also Given: m = 1612 kg
Substitute into equation 2
F = 1612(3.71)
F = 5980.52 N.
Finally,
Substitute into equation 1
P = 5980.52×12.87
P = 76969.29 W
Answer:
C- what is determined as right or wrong is universally defined and agreed upon.
Explanation:
Correct on edge
Answer:They stop because jet streams follow boundaries between hot and cold air.
Explanation:
Answer:
![a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=a%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)
Explanation:
According to Newton's Third Equation of motion
![V_f^2-V_i^2=2as](https://tex.z-dn.net/?f=V_f%5E2-V_i%5E2%3D2as)
Where:
is the final velocity
is the initial velocity
a is the acceleration
s is the distance
In our case:
![V_f=V_{escape}, V_i=0,s=4 m](https://tex.z-dn.net/?f=V_f%3DV_%7Bescape%7D%2C%20%20V_i%3D0%2Cs%3D4%20m)
So Equation will become:
![V_{escape}^2-V_i^2=2as\\V_{escape}^2-0=2as\\V_{escape}^2=2as\\a=\frac{V_{escape}^2}{2s}\\a=\frac{(5*10^3m)^2}{2*4}\\a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=V_%7Bescape%7D%5E2-V_i%5E2%3D2as%5C%5CV_%7Bescape%7D%5E2-0%3D2as%5C%5CV_%7Bescape%7D%5E2%3D2as%5C%5Ca%3D%5Cfrac%7BV_%7Bescape%7D%5E2%7D%7B2s%7D%5C%5Ca%3D%5Cfrac%7B%285%2A10%5E3m%29%5E2%7D%7B2%2A4%7D%5C%5Ca%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)