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blagie [28]
2 years ago
13

What do I feed my pet fly

Physics
2 answers:
algol132 years ago
7 0
You can feed your pet fly pretty much anything that’s high in sugar. It’s better to feed them a liquid rather then a solid, so sugary drinks are preferable.

Hope this helps <3
KatRina [158]2 years ago
6 0

Answer:

If she ___(be) rich, she _____ (buy) a new sports car.

Group of answer choices

is/buys

be/buy

were/would buy

were/bought

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When a rocket is 4 kilometers high, it is moving vertically upward at a speed of 400 kilometers per hour. At that instant, how f
Y_Kistochka [10]

Answer:

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

Explanation:

Geometrically speaking, the distance between the rocket and the observer (r), measured in kilometers, can be represented by a right triangle:

r = \sqrt{x^{2}+y^{2}} (1)

Where:

x - Horizontal distance between the rocket and the observer, measured in kilometers.

y - Vertical distance between the rocket and the observer, measured in kilometers.

The angle of elevation of the rocket (\theta), measured in sexagesimal degrees, is defined by the following trigonometric relation:

\tan \theta = \frac{y}{x} (2)

If we know that x = 5\,km, then the expression is:

\tan \theta = \frac{y}{5}

And the rate of change of this angle is determined by derivatives:

\sec^{2}\theta \cdot \dot \theta = \frac{1}{5}\cdot \dot y

\frac{\dot \theta}{\cos^{2}\theta} = \frac{\dot y}{5}

\frac{\dot \theta\cdot (25+y^{2})}{25} = \frac{\dot y}{5}

\dot \theta = \frac{5\cdot \dot y}{25+y^{2}}

Where:

\dot \theta - Rate of change of the angle of elevation, measured in sexagesimal degrees.

\dot y - Vertical speed of the rocket, measured in kilometers per hour.

If we know that y = 4\,km and \dot y = 400\,\frac{km}{h}, then the rate of change of the angle of elevation is:

\dot \theta = 48.780\,\frac{\circ}{s}

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

3 0
3 years ago
The launch speed of a projectile is three times the speed it has at its maximum height.what is the elevation angle at launch?
Sphinxa [80]

Answer:

Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.

6 0
2 years ago
After crossing the finish line, a race car slows down from 47 m/s to 32m/s in 3seconds. What is the car’s acceleration?
Lisa [10]

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

7 0
3 years ago
High voltage power is often carried in wire bundles made up of individual strands. In your initial post to the discussion, discu
Firdavs [7]

Answer:

<em>There will  be a huge problem of holding the wire strands together, and the power losses will also be amplified.</em>

Explanation:

The force per unit length on two current carrying conductors, lying parallel to each other is proportional to the product of the current through the conductors, and inversely proportional to their distance apart. This force is attractive if the current flows through these conductors in the same direction, and is repulsive if it flows in the opposite direction.

For the strand of wire that make up a high voltage wire bundle, there will be a force of attraction pulling the wires closer to each other, and they will experience the maximum pulling force possible, since they lie next to each other. This force helps to hold these wires in a high tension wire strand together, limiting the area, and reducing "skin effect."

In the case that this wires in the wire strand acts in opposite of the known behavior, the wires will repel and push each other apart. This pushing apart will increase power loss due "skin effect" which is increased by an increase in exposed surface area of the wire strands. This will pose a big problem for high tension transmission.

6 0
3 years ago
After a nucleus with 85 protons undergoes alpha decay, it has<br><br> ? protons.
Valentin [98]

Answer:

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

Explanation:

In an alpha particle there are two protons

In the given substance's nucleus, there are total of 85 protons

After the decay, the proton number reduce

The current proton number after decay is

85 -2 = 83

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

5 0
3 years ago
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