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blagie [28]
2 years ago
13

What do I feed my pet fly

Physics
2 answers:
algol132 years ago
7 0
You can feed your pet fly pretty much anything that’s high in sugar. It’s better to feed them a liquid rather then a solid, so sugary drinks are preferable.

Hope this helps <3
KatRina [158]2 years ago
6 0

Answer:

If she ___(be) rich, she _____ (buy) a new sports car.

Group of answer choices

is/buys

be/buy

were/would buy

were/bought

You might be interested in
In a nuclear fusion reaction, the mass of the products is _____ the mass of the reactants.
JulijaS [17]

Answer:

more than

Explanation:

In a nuclear fusion reaction, the mass of the products is more than the mass of the reactants.

7 0
3 years ago
In your own words, define the following terms.<br> 2. climate___________.
qwelly [4]

Answer:

The state of a certain type of land or a biome.

5 0
1 year ago
A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
3 years ago
A 20N net force acts upon an object with a mass of 4. 0kg. What is the object's acceleration?
galina1969 [7]

Answer:

5ms^-2

Explanation:

F = 20N, m = 4.0kg, a = ?

Using the formula for Force

F = ma

Then making acceleration the subject of the formula

a = F/m

a = 20N/4.0kg

a = 5ms^-2

8 0
2 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n
qwelly [4]

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × 10^{-21} = 9 × 10^{9} × (n × 1.602 × 10^{-19})² /0.2²

solving for n

n = 759

4 0
3 years ago
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