Answer:
0.657 seconds
Explanation:
speed of wave= wavelength / time period
so
time period= wavelength / speed
= 4.6/7
=0.657 sec
Answer:
f = 735 Hz
Explanation:
given,
Person distance from speakers
r₁ = 4.1 m r₂ = 4.8 m
Path difference
d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m
For destructive interference

where, n = 1, 3,5..
we know, λ = v/f

v is the speed of the sound = 343 m/s
f is the frequency

for n = 1

f = 245 Hz
for n = 3

f = 735 Hz
Hence,the second lowest frequency of the destructive interference is 735 Hz.
Answer: 655.7 nm
Explanation:
Given
The slits are separated by 
Distance between slits and screen is 
Adjacent bright fringes are
apart
Also, the distance between bright fringes is given by
![\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cbeta%20%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D%5Cquad%20%5B%5Clambda%3D%5Ctext%7BWavelength%20of%20light%7D%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5C%5C%5CRightarrow%202.88%5Ctimes%2010%5E%7B-3%7D%3D%5Cdfrac%7B%5Clambda%20%5Ccdot%202.24%7D%7B0.510%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D%5Cdfrac%7B2.88%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.510%5Ctimes%2010%5E%7B-3%7D%7D%7B2.24%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D0.6557%5Ctimes%2010%5E%7B-6%7D%5C%20m%5C%5C%5CRightarrow%20%5Clambda%20%3D655.7%5C%20nm)