What can you assume about the anions in the ionic compound copper(II) fluoride? A. The charge on the ionic compound is 2+.
1 answer:
The answer is C, because if the copper has a +2 charge, the fluoride must have a -2 charge in order to cancel out.
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Answer:
Explanation:
x in (-oo:+oo)
2 < (1/2)*x-3 // - (1/2)*x-3
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x > -5/(-1/2)
x > 10
x in (10:+oo)
(10:+oo)
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Explanation:
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