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9966 [12]
3 years ago
14

What can you assume about the anions in the ionic compound copper(II) fluoride? A. The charge on the ionic compound is 2+.

Chemistry
1 answer:
erastova [34]3 years ago
4 0
The answer is C, because if the copper has a +2 charge, the fluoride must have a -2 charge in order to cancel out.
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balance the following equation by oxidation number method KMnO4 + Na2So3 gives Mno2 + Na2 So4 + Koh​
belka [17]

Answer:

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Explanation:

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7 0
3 years ago
1. How many protons does 14/6 C contain? What element is this?
Harman [31]

Answer:

It has 6 protons and its Carbon 14

Explanation:

3 0
3 years ago
I need help with this question ​
VARVARA [1.3K]

Answer:

2.25×10¯³ mm.

Explanation:

From the question given above, we obtained the following information:

Diameter in micrometer = 2.25 μm

Diameter in millimetre (mm) =?

Next we shall convert 2.25 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

2.25 μm = 2.25 μm / 1 μm × 1×10¯⁶ m

2.25 μm = 2.25×10¯⁶ m

Finally, we shall convert 2.25×10¯⁶ m to millimetre (mm) as follow:

1 m = 1000 mm

Therefore,

2.25×10¯⁶ m = 2.25×10¯⁶ m /1 m × 1000 mm

2.25×10¯⁶ m = 2.25×10¯³ mm

Therefore, 2.25 μm is equivalent to 2.25×10¯³ mm.

6 0
3 years ago
Fluorine + sodium chloride → sodium fluoride + __________. What is the missing chemical name?
Deffense [45]

Answer:

Chlorine (Cl)

Explanation:

The equation would be:

F+NaCl  → NaF + Cl

This is because no atom is lost in a reaction. Chlorine would be the missing chemical as it is on the other side of the equation and needs to be accounted for on the products side.

7 0
2 years ago
How many milliliters of a stock solution of 12.1 M HNO3 would be needed to prepare 0.500 L of 0.500 M HNO3
AnnZ [28]

Answer:

(5.00M)(X) = (0.120L)(0.470M)

 

X = (0.120)(0.470)/(5.00)

0.01128

Explanation:

7 0
2 years ago
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