Answer:
0.22 b
Explanation:
Quadrupole moment of the nucleon is,
And also,
And, 
Now,
For Bismuth 
and A is 209.
Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b
The acceleration of the object which moves from an initial step to a full halt given the distance traveled can be calculated through the equation,
d = v² / 2a
where d is distance, v is the velocity, and a is acceleration
Substituting the known values,
180 = (22.2 m/s)² / 2(a)
The value of a is equal to 1.369 m/s²
The force needed for the object to be stopped is equal to the product of the mass and the acceleration.
F = (1300 kg)(1.369 m/s²)
F = 1779.7 N
Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
Distance travelled S = ut + (at^2)/2
Substituting the values in the second equation of motion,
S = 50*2 + (10 * 2 *2)/2
S = 100 + 20
S = 120 miles
Therefore the distance travelled by the car in the next two hours is 120 miles
Answer:
E=72000J or 72kj
Explanation:
The formula is E=pt you need to convert your t from minutes to seconds before proceeding
Weight = (mass) x (gravity)
120 N = (mass) x (9.8 m/s²)
Mass = (120 N) / (9.8 m/s²)
Mass = 12.24 kg (B)
