Explanation:
the correct answer is Option 5.√½gh.
hope this helps you.
Answer:
The value is
Explanation:
Generally the moon's radial acceleration is mathematically represented as
Here
is the angular velocity which is mathematically represented as

substituting
for T(i.e the period of the moon ) we have
=>
From the question r(which is the radius of the orbit ) is evaluated as

substitute
for R and
H

=> 
So
Find the acceleration:
v² - u² = 2ax
(v = final velocity, u = initial velocity, a = acceleration, x = displacement)
(82.0 m/s)² - 0² = 2 a (0.400 m)
a = (82.0 m/s)² / (2 (0.400 m))
a = 8405 m/s²
Find the time:
x = ut + 1/2 at²
(t = time)
0.400 m = 0 + 1/2 (8405 m/s²) t²
t² = (0.400 m) / (1/2 (8405 m/s²))
t = √((0.400 m) / (1/2 (8405 m/s²)))
t ≈ 0.00976 s