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3 years ago

Please help

Physics

1 answer:

ivanzaharov [21]3 years ago

4 0

Answer:

1 +2=3 so thats it

Explanation:

Because i need points

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an object has a momentum of 250 kg m/s what would be the momentum of an object that has half of the mass and going at the same v

Romashka-Z-Leto [24]

The momentum of the second object is 125 kg m/s

Explanation:

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem,

$p = 250 kg m/s$

And its mass is m and its velocity is v.

The second object has a mass of $m' = \frac{m}{2}$ and same velocity v, so its momentum is

$p'=m'v = (\frac{m}{2})v=\frac{1}{2}(mv)=\frac{1}{2}p$

So, the second object has a momentum that is half of the momentum of the first object, therefore it is:

$p'=\frac{1}{2}(250)=125 kg m/s$

Learn more about momentum:

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3 years ago

A proton traveling with speed 2 × 105 m/s in the -y direction passes through a region in which there is a uniform magnetic field

stepladder [879]

Answer:

$\vec{E} = 1.2\times 10^5(-i)$

Explanation:

Given that

Speed ,v= 2 x 10⁵ m/s ( - y direction)

B= 0.6 T (- z direction)

The resultant force on the proton given as

$\vec{F}=q.\vec{E}+ q.(\vec{v}\times \vec{B})$

F= m a

For uniform motion acceleration should be zero.

F = 0

$0=q.\vec{E}+ q.(\vec{v}\times \vec{B})$

$0=\vec{E}+ (\vec{v}\times \vec{B})$

$0=\vec{E}+2\times 10^5(-j) \times 0.6(-k)$

$\vec{E} =- 2\times 10^5(-j) \times 0.6(-k)$

$\vec{E} =-1.2\times 10^5(i)$

$\vec{E} = 1.2\times 10^5(-i)$

Electric filed should be apply in the negative x direction.

5 0

3 years ago

A thin glass rod is submerged in oil. What is the critical angle for light traveling inside the rod? The index of refraction for

Alekssandra [29.7K]

When light travels from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle of incidence above which light is reflected only (no refraction occurs), and the value of this critical angle is given by
$\theta_c = \arcsin ( \frac{n_2}{n_1} )$
where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.

In this problem, the first medium is the glass ( $n_1 = 1.50$ ), while the second medium is oil ( $n_2 =1.46$ ), therefore the critical angle is given by
$\theta_c = \arcsin( \frac{1.46}{1.50} )=\arcsin(0.973)=76.7^{\circ}$

7 0

3 years ago

How much work done when .0080 C is moved through a potential difference of 1.5 V? Use W = qV. A.

grin007 [14]

Answer:

0.012 J

Explanation:

We are given:

q = 0.0080C

Potential difference = 1.5V

W=qV

Substituting the values into the equation:

W=0.0080*1.5= 0.012J

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3 years ago

35. (II) A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging on a 2.8-m long string, which makes th

pentagon [3]

Answer:

Explanation:

Let mass of bullet = m1 = 28g= 0.028 kg

mass of pendulum = m2 = 3.1 kg

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3 years ago