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geniusboy [140]
3 years ago
8

Waves that require a medium through which to travel are electromagnetic waves. True or False?

Chemistry
2 answers:
aev [14]3 years ago
8 0

Answer:

True

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate.

12345 [234]3 years ago
3 0

Waves that require medium through which to travel are “electromagnetic waves”? Yes this is “TRUE”

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The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
3 years ago
Read 2 more answers
If the density of pure water is 0.9922 g/mL at 40 ºC, calculate its theoretical molarity at that temperature. Report to 4 sig fi
OleMash [197]
Answer is: theoretical molarity of water is 55.1222 mol/L.<span>
d(H</span>₂O) = 0.9922 g/mL.
M(H₂O) = 2 · Ar(H) + Ar(O) · g/mol.
M(H₂O) = 2 + 16 · g/mol = 18 g/mol.
c(H₂O) = d(H₂O) ÷ M(H₂O).
c(H₂O) = 0.9922 g/mL ÷ 18 g/mol.
c(H₂O) = 0.0551 mol/mL.
c(H₂O) = 0.0551 mol/mL · 1000 mL/L = 55.1222 mol/L.
3 0
4 years ago
28° 51' 55" W
Nezavi [6.7K]

Answer: good                  

Explanation:  its fun

4 0
3 years ago
The graph below shows how the temperature and volume of a gas vary when
Sever21 [200]

Answer:

C

Explanation:

because it remains the same

3 0
3 years ago
The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo
GaryK [48]

Answer:

D)subscript of C in molecular formula = n x subscript of C in empirical formula

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />

An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is

A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.

Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula

8 0
3 years ago
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