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geniusboy [140]
3 years ago
8

Waves that require a medium through which to travel are electromagnetic waves. True or False?

Chemistry
2 answers:
aev [14]3 years ago
8 0

Answer:

True

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate.

12345 [234]3 years ago
3 0

Waves that require medium through which to travel are “electromagnetic waves”? Yes this is “TRUE”

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A stretched rubber band is an example of:
klio [65]

Answer:

Potential Energy

Explanation:

Not sure how to explain it but C and D could be crossed off as answers, kinetic energy would be if it was released (?)

sorry if im wrong

3 0
2 years ago
Define the terms (a) sedimentation ( b )decantation​
Nataly_w [17]

Answer:

  • Sedimentation: Sedimentation is the process of allowing particles in suspension in water to settle out of the suspension under the effect of gravity.
  • Decantation: Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture

hope u liked the answer :)

7 0
2 years ago
Read 2 more answers
Can you help me on this stuff
Ostrovityanka [42]

(D)- Sea breezes are local winds that blow from an ocean or a lake

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7 0
3 years ago
A 1 liter solution contains 0.247 M nitrous acid and 0.329 M sodium nitrite. Addition of 0.271 moles of calcium hydroxide will:
Inessa05 [86]

Answer:

a. Raise the pH slightly

Explanation:

We know that

Pka of HNO2/KNO2 =3.39

Moles of HNO2 in the buffer=0.247 mol/L×1L=0.247 moles

Moles of NO2-=0.329mol/L×1L=0.329 moles

If 0.271 moles of Ca(OH)2 is added it will neutralise 0.136 moles of acid ,HNO2,remaining HNO2=0.247-0.136=0.111 moles

Moles of NO2- will increase as 0.0333 moles Ca(NO)2 will be formed =0.0333+0.036=0.0693 moles

pH=pka+log [base]/[acid]      {henderson -hasselbach equation}

=3.39+log (0.0693/0.0317)=3.39+0.34=3.73

pH=3.73

4 0
3 years ago
I need help with with number 1515. How many moles of NO2 are in a 37.058 L container at 101.28 kPa and -139.86
Andre45 [30]

Explanation:

To solve this question, we will use the Clayperon Equation:

P.V = n.R.T

where:

P = 101.28 kPa

1 atm = 101,325 Pa

x atm = 101,280 Pa

x = 1 atm

V = 37.058 L

n = we don't know

R = 0.082 atm.L/K.mol

T = -139.88 ºC = -139.88+273.15 = 133.27 K

1*37.058 = n*0.082*133.27

n = 0.29 moles

Answer: 0.29 moles

5 0
8 months ago
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