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3 years ago

In the combustion of ethane, what is/are the reactant(s)?

2 answers:

8 0

Organic matter usually produce Carbon Dioxide and Water as its products.
Answer is A for products.
Reactants will be ethane and oxygen
Ethane has 2 carbons. so B is the answer.

aleksley [76]3 years ago

5 0

Reactant are those that combine or reacts to give products !!

so in combustion of ethane ; ethane and o2 are reactants so ... your answer is B !!

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This stadium can hold 100,000, or 1 x 10^5, people. The number of atoms in a grain of iron is about 1 x 10^18. Would you need 1

polet [3.4K]

<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

From the question;

1 x 10^5 people can fill 1 stadium

We are given, 1 x 10^18 atoms of iron

We are required to determine the number of stadiums that 1 x 10^18 atoms of iron would occupy.

We are going to assume that a stadium would occupy a number of atoms equivalent to the number of people.

Therefore;

One stadium = 1 x 10^5 atoms

Then, to find the number of stadiums that will be occupied by 1 x 10^18 atoms;

No. of stadiums = Total number of atoms ÷ Atoms in a single stadium

= 1 x 10^18 atoms ÷ 1 x 10^5 atoms

= 1 x 10^13 stadiums

Therefore, 1 x 10^18 atoms of iron would occupy 1 x 10^13 stadiums

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2 years ago

Select all that apply.

MakcuM [25]

Answer:

A telescope, printing press, and microscope

Explanation:

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3 years ago

All substances freeze at the same temperature, so they all have exactly the

Anastasy [175]

Answer:

I think it would be false

Explanation:

All things have a unique freezing/melting point

6 0

3 years ago

The length of a diagonal of a cube with edge length 3 in.

Lilit [14]

Answer:

Diagonal

5.196

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2 years ago

The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

3 0

3 years ago