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Sergio039 [100]
3 years ago
13

A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T on Earth. Calculate the

new period of oscillation in terms of T1. on Earth, if the mass of the bob is reduced by half.A.2TB.T2C.TD.√2T
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

T = T

Explanation:

Time period of a simple pendulum is not affected by the mass of the bob. As we know, T = 2\pi \sqrt{L/g} . There is no factor of mass affecting when we derived the equation. The basic reason behind the time period is not affected is because of mass dependence on angular acceleration. As the mass increases the acceleration increase and the Time Period remains constant.

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Svetradugi [14.3K]

Answer:

false

Explanation:

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7 0
3 years ago
How long will it take a ball to roll 10 meters along the floor at a speed of 0.5 m/s?
IRINA_888 [86]

Answer:

20 seconds.

Explanation:

The following data were obtained from the question:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

The speed of an object is simply defined as the distance travelled by the object per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the time taken for the ball to travel a distance of 10 m as shown below:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

Speed = Distance /time

0.5 = 10/time

Cross multiply

0.5 × time = 10

Divide both side by 0.5

Time = 10/0.5

Time = 20 secs.

Therefore, it will take 20 seconds for the ball to travel a distance of 10 m.

6 0
3 years ago
1) Which of the following statements about physical models is not true?
Alex_Xolod [135]
1. "<span>Physical models are usually in the form of a graph" is the statement among the statements given about physical models that is not true. The correct option among all the options that are given in the question is the third option or option "c".

2. "Predicting weather patterns" is the one among the following scenarios that </span>represents the best use of a scientific model. <span>The correct option among all the options that are given in the question is the first option or option "a".</span>
8 0
3 years ago
Which formula can be used to calculate the horizontal displacement of a horizontally launched projectile?
Jet001 [13]
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7 0
3 years ago
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s
nevsk [136]

a) 0.94 m

The work done by the snow to decelerate the paratrooper is equal to the change in kinetic energy of the man:

W=\Delta K\\-F d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where:

F=1.1 \cdot 10^5 N is the force applied by the snow

d is the displacement of the man in the snow, so it is the depth of the snow that stopped him

m = 68 kg is the man's mass

v = 0 is the final speed of the man

u = 55 m/s is the initial speed of the man (when it touches the ground)

and where the negative sign in the work is due to the fact that the force exerted by the snow on the man (upward) is opposite to the displacement of the man (downward)

Solving the equation for d, we find:

d=\frac{1}{2F}mu^2 = \frac{(68 kg)(55 m/s)^2}{2(1.1\cdot 10^5 N)}=0.94 m

b) -3740 kg m/s

The magnitude of the impulse exerted by the snow on the man is equal to the variation of momentum of the man:

I=\Delta p = m \Delta v

where

m = 68 kg is the mass of the man

\Delta v = 0-55 m/s = -55 m/s is the change in velocity of the man

Substituting,

I=(68 kg)(-55 m/s)=-3740 kg m/s

7 0
3 years ago
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