A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T on Earth. Calculate the
1 answer:
Answer:
T = T
Explanation:
Time period of a simple pendulum is not affected by the mass of the bob. As we know, . There is no factor of mass affecting when we derived the equation. The basic reason behind the time period is not affected is because of mass dependence on angular acceleration. As the mass increases the acceleration increase and the Time Period remains constant.
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Answer:
u = - 20 cm
m =
Given:
Radius of curvature, R = 10 cm
image distance, v = 4 cm
Solution:
Focal length of the convex mirror, f:
f =
Using Lens' maker formula:
Substitute the given values in the above formula:
u = - 20 cm
where
u = object distance
Now, magnification is the ratio of image distance to the object distance:
magnification, m =
magnification, m =
m =
m =
The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>- As we know that the expression of pressure as,
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,
- From this, the value of weight will be,
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
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