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3 years ago

6

What is newton second law definition?

2 answers:

dybincka [34]3 years ago

6 0

Answer:

the acceleration of an object is dependent upon two variables the net force acting upon the object and the mass of the object

Bess [88]3 years ago

3 0

Answer:

Newton's 2nd law states that the acceleration of a moving object depends on the net force and the mass of the object. According to the formula, the force can be found by multiplying the mass by the objects acceleration. The equation is "Force = mass * acceleration."

Explanation:

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Which statement is a characteristic of a concave lens?

Trava [24]

D. it is thickest in the middle

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3 years ago

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you want to get more physically fit but often make excuses for why you don't have time to be active what strategy can help with

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3 years ago

Orange light of wavelength 0.61 µ m in air enters a block of glass with εr = 1.44. What color would it appear to a sensor embedd

77julia77 [94]

Answer:

$0.5083\ \mu m$

Explanation:

$\lambda_0$ = Actual wavelength = $0.61\ \mu m$

$\varepsilon_r$ = Relative permittivity = 1.44

The observed wavelength in the glass is given by

$\lambda=\dfrac{\lambda_0}{\sqrt{\varepsilon_r}}\\\Rightarrow \lambda=\dfrac{0.61}{\sqrt{1.44}}\\\Rightarrow \lambda=0.5083\ \mu m$

The wavelength lies in the range of green light.

Hence, the observed color of light is $0.5083\ \mu m$

8 0

3 years ago

A leaky 10-kg bucket is lifted from the ground to a height of 10 m at a constant speed with a rope that weighs 0.9 kg/m. Initial

sladkih [1.3K]

Answer:

The work done shall be 14715 Joules

Explanation:

The work done by a force 'F' in a displacement 'dy' is given by

$W=m(y)g\times dy$

At any position 'y' the weight shall be sum of weft of water and weight of string

$\therefore m(y)=m_{water}(y)+m_{string}(y)\\\\m(y)=30(1-\frac{y}{10})+0.9y$

Thus applying values we get

$W=\int m(y)g\times dy\\\\W=\int_{0}^{10}(30(1-\frac{y}{10}+0.9y)\times g)dy\\\\Solving\\W=294.3\int_{0}^{10}(1-\frac{y}{10}+0.9y)dy\\\\W=14715J$

8 0

3 years ago

Newton’s empirical law of cooling/warming of an object is given by ( ), T Tm k dt dT = − where k is a constant of proportionalit

pychu [463]

Answer:

The time for the cake to cool off to room temperature is

approximately 30 minutes.

Let $T_{0}$ = $70^{0}$ F be the temperature and T that of the body

Explanation:

Our Tm = 70, the initial-value problem is

$\frac{DT}{dt}$ = <em>k</em>(T − 70), T(0) = 300

Solving the equation, we get

$\frac{DT}{t-70}$ = <em>kdt</em>

In [T-70]= <em>kt </em>+ $C_{1}$

T = 70 + $C_{2}$ $e^{kt}$

Finding he value for $C_{2}$ using the initial value of T (0)= 300, therefore we get:

300=70+ $C_{2}$

$C_{2}$ = 230 therefore

T= 70+ 230 $e^{kt}$

Finding the value for <em>k </em>using T (3) = 200, therefore we get

T (3) = 200

$e^{3k}$ = $\frac{13}{23}$

<em>K </em>= $\frac{1}{3}$ in $\frac{13}{23}$

= -0.19018

Therefore

T(t) = 70+230 $e^{-0.19018}$

4 0

3 years ago