Answer:
Step-by-step explanation:
3.2 times 1.5 plus 6 times4.2= 30 meters of carpet.
You have to look for -3 on the x axis, and then proceed vertically (in this case upwards) until you meet the graph.
We land about 1/2 square above the 12 mark on the y axis. Since one square is 1/2 unit, a half square would be 1/4 unit.
So, we can estimate 
Answer:
The width of member is as follows:
b = 3 ft
b = 3 × 12 in.
b= 36 in.
The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in.
Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi
Calculate the net area of the member as follows:
A = (b - ∅) × d
A= (36 - 7/8) × 96

Calculate the maximum axial tensile load by ASD method as follows:
P = f × A
P = 1000 x 3372
P = 3372000 lbs
P = 3372 kips
So first, you want to isolate your Y. To do this, you must get it alone on ONE SIDE of the equation.
5x - 2y = 3
-5x -5x
= 
ANSWER: y = \frac{3-5x}{-2}