Answer:

Explanation:
Given:
electric field, 
charge, 
initial position coordinates, 
final position coordinates, 
We find the distance through which the charge has been moved:

Where we have (x1,y1) & (x2,y2) as the initial and final coordinates of the points.


Now we need the angle through which displacement is made with respect to the direction of electric field.

![\theta= tan^{-1}[\frac{76-(-131)}{107-(-81)} ]](https://tex.z-dn.net/?f=%5Ctheta%3D%20tan%5E%7B-1%7D%5B%5Cfrac%7B76-%28-131%29%7D%7B107-%28-81%29%7D%20%5D)

Now from the relation between the change in potential difference:



∵The change in voltage is defined as the work done per unit charge.
∴

Putting the respective values


Any force of 29.4 Newtons or greater can do it.
95km/h
95km/60*60sec
(95/(60*30))km/2sec
0.05277km