Use Net Force Equation.
Fnet = F1 + F2 + F3 + F4
In which the following main forces in play are:
F1 = Gravitational Force
F2 = Normal Force
F3 = Thrust Force
F4 = Air resistance
Since this is assumed to happen on a flat surface, the gravitational and normal forces cancel out. So we are left with:
Fnet = F(thrust) + F(air resistance)
Now we can use this equation to solve for the net force.
Fnet = 10N [right] + 7N [left]
Fnet = 10N [right] - 7N [right]
Fnet = 3N [right].
Therefore, the total net force acting on this car would be 3N [right]
Momentum formula - P=MV
P=MV
P= (3.5 kg)(6 m/s) - multiply
P= 21 kg x m/s to the east
Hope this helps
<span>In this particular case, where car is moving through curvature, so it is moving in circular motion, force acting on car is centripetal force which holds car not to fly out. Centripetal force is always pointed in the middle of circle. Here frictional force has role of centripetal force. If frictional force is to weak, car would fly out of curvutare.</span>
Bit of an odd question. Power Plants are known to use water-powered turbines to generate electricity, but can also make use of nuclear fission.
Answer:
60 rad/s
Explanation:
∑τ = Iα
Fr = Iα
For a solid disc, I = ½ mr².
Fr = ½ mr² α
α = 2F / (mr)
α = 2 (20 N) / (0.25 kg × 0.30 m)
α = 533.33 rad/s²
The arc length is 1 m, so the angle is:
s = rθ
1 m = 0.30 m θ
θ = 3.33 rad
Use constant acceleration equation to find ω.
ω² = ω₀² + 2αΔθ
ω² = (0 rad/s)² + 2 (533.33 rad/s²) (3.33 rad)
ω = 59.6 rad/s
Rounding to one significant figure, the angular velocity is 60 rad/s.
