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Alexeev081 [22]
3 years ago
12

How many minutes in a century?

Physics
2 answers:
den301095 [7]3 years ago
5 0
About equalivent to 52.6 million
Nutka1998 [239]3 years ago
3 0

Answer:

52,596,000

Explanation:

You might be interested in
At which type of boundary between two tectonic plates is an earthquake or a tsunami most likely to form?
Fofino [41]

Answer:

B. convergent boundary

Explanation:

Convergent boundaries, where ocean plates are subducted at trenches, produce the most tsunamis because they produce the largest earthquakes

7 0
3 years ago
Which one of the following is not a derived quantity a)speed b)velocity c)time d)force​
qaws [65]

Answer:

c) time

Explanation:

time is a fundamental quantity from which other quantities are derived

5 0
3 years ago
Example of what does future scientist think about the universe
nadezda [96]
Are you asking us what we think of the universe? lol
3 0
4 years ago
A rock is dropped at the same instant that a ball at the same height is thrown horizontally. which will will have the greater sp
Svetach [21]
They will both hit the ground at the same time due to gravity.
that means they took the same time to travel the distance to the ground

however, the ball traveled farther
speed=distance (or displacement) divided by time
so the greater the distance, the greater the speed

the ball traveled faster in the same time so it traveled faster

answer is ball

5 0
3 years ago
If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76
den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

F=mg

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

F=(78.0)(9.8)=764.4 N

(b) 21.1 N

The spacecraft is located at a distance of

r=6R

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

GM=9.8R^2 (1)

the acceleration due to gravity at r=6R instead will be

g'=\frac{GM}{(6R)^2}

And substituting (1) into this formula,

g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2

So the weight of the astronaut at the spacecratf location is

F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N

6 0
4 years ago
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