Answer:
(A). The tension in the rope that connects the boxes is 10.50 N.
(B). The value of m is 7 kg.
Explanation:
Given that,
Mass of box B = 5.00 kg
Mass of box A = m
Force = 40.0 N
Direction= 53.1°
Acceleration = 1.50 m/s²
Coefficient of kinetic friction = 0.30
(A). We need to calculate the tension in the rope that connects the boxes
Using balance equation

Put the value into the formula


(B). We need to calculate the value of m
Using formula of tension


Put the value into the formula


Hence, (A). The tension in the rope that connects the boxes is 10.50 N.
(B). The value of m is 7 kg.