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2 years ago

8

Two identical circular plates have a diameter of 8.2 cm. They are placed parallel to each other separated by a distance of 2.1 m

m. What is the capacitance if paper, with a k-3.7, is placed between the plates? O 92 pF O 82 p O 62 pF ? 13oF

1 answer:

Andrei [34K]2 years ago

6 0

Answer:

82 pF

Explanation:

diameter = 8.2 cm, distance, d = 2.1 mm = 0.0021 m,

dielectric constant, k = 3.7

radius = 1/2 x diameter = 8.2 / 2 = 4.1 cm = 0.041 m

The formula for the capacitance of parallel plate capacitor is given by

$C = \frac{k \varepsilon _{0}\times A}{d}$

$C = \frac{3.7 \times 8.854\times 10^{-12} \times \pi \times 0.041 \times 0.041}{0.0021}$

C = 8.23 x 10 ^-11 F

C = 82 pF

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3 years ago

A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3.0 km/h

Yuki888 [10]

Answer:

The magnitude of F₁ is 3.7 times of F₂

Explanation:

Given that,

Time = 10 sec

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$v_{1}=\dfrac{3.0\times10^{3}}{3600}$

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Similarly,

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For total force,

$F_{3}=F_{2}+F_{1}$

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The speed of second tugboat is

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$v=3.05\ m/s$

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$a_{3}=\dfrac{v}{t}$

$a_{3}=\dfrac{3.05}{10}$

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We need to calculate the acceleration a₂

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$a_{2}=0.305-0.083$

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$\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}$

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Explanation:

Given data

speed of sound = 343 m/s

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solution

let us consider depth d

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depth = 1/2 ×g ×t² ..............1

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depth = velocity of sound × time .................2

here we have given time 6.25 that is sum of 2 time

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another is sound reach us after stone strike on bottom

so time 1 + time 2 = 6.25 s

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