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maxonik [38]
3 years ago
15

Would an oil ship moving at a speed of 10km/h have more or less momentum than a car moving at a speed of 100km/h? Explain your a

nswer
Physics
2 answers:
Rufina [12.5K]3 years ago
7 0

Answer:

Multiply the mass times the speed for both, then compare.I would expect the mass of the oil ship to be more than 10 times the mass of the car, in which case its momentum would be greater.

PLZ MARK BRAINLIEST

lesantik [10]3 years ago
3 0

Answer: The ship has more momentum

Explanation: The momentum is defined as the amount of motion of an object, and it can be calculated as:

P = M*v

Where M is the mass and v is the velocity.

So we know that the velocity of an oil ship is around 10km/h and one of the cars is around 100km/h (the velocity of the car is 10 times the one of the ship)

But the mass of the oil ship is a lot bigger than the one of the car, for example, a car weighs around 2900 pounds, and an average oil ship carries a few hundred tons of oil, where a ton is 2000 pounds, so the mass of the oil ship is (only in the charge) around 100 times bigger than the one of the car, so the momentum of the ship will be a lot bigger than the one of the car.

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A lady bug is sitting on the bottom of a can while you twirl it overhead on a string that is 65.0
MA_775_DIABLO [31]

The linear speed of the ladybug is 4.1 m/s

Explanation:

First of all, we need to find the angular speed of the lady bug. This is given by:

\omega=\frac{2\pi}{T}

where

T is the period of revolution

The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:

T = 1 s

Therefore, the angular speed is

\omega=\frac{2\pi}{1 s}=6.28 rad/s

Now we can find the linear speed of the ladybug, which is given by

v=\omega r

where:

\omega=6.28 rad/s is the angular speed

r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation

Substituting, we find

v=(6.28)(0.65)=4.1 m/s

Learn more about angular speed:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

7 0
3 years ago
A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci
Simora [160]

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

4 0
2 years ago
The electric potential at the origin of an xy-coordinate system is 40 V. A -8.0-μC charge is brought from x = +∞ to that point.
vredina [299]

Answer:

-320 μJ.

Explanation:

Consider a point with an electrical charge of q. Assume that V is the electrical potential at the position of that charge. The electrical potential of that point charge will be equal to:

\text{Potential Energy} = q \cdot V.

Keep in mind that since both q and V might not be positive, the size of the electrical potential energy might not be positive, either.

For this point charge,

  • q = \rm -8.0\; \mu C; (that's -8.0 microjoules, which equals to \rm -8.0\times 10^{-6}\; J)
  • V = \rm 40\; V.

Hence its electrical potential energy:

\text{Potential Energy} = q\cdot V = \rm (-8.0\; \mu C) \times 40\; V = -320\; \mu J.

Why is this value negative? The electrical potential energy of a charge is equal to the work needed to bring that charge from infinitely far away all the way to its current position. Also, negative charges are attracted towards regions of high electrical potential. Bringing this \rm -8.0\; \mu C negative charge to the origin will not require any external work. Instead, this process will release 320 μJ of energy. As a result, the electrical potential energy is a negative value.

7 0
3 years ago
HURRY 20 POINTS <br><br><br> Why is it important to include exercise in your daily routine?
Sedbober [7]

Explanation:

it can improve muscle strength and boost your endurance.

it also delivers oxygen and nutrients to your tissues

3 0
2 years ago
10. 1. Why is Newton's law of gravitation called universal law ?​
Eduardwww [97]

Newtons law of gravitation is called the universal law of gravitation because it is applicable for all masses at all distances, independent of the medium.

6 0
2 years ago
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